Question

我在尝试获取请求状态时一直收到此错误。

这是我的代码

ExpenseRepository.php

<?php

namespace Expensetrim\Api\v1\Repositories;

use Auth;
use GuzzleHttp\Client;
use GuzzleHttp\Exception\RequestException;
use Expensetrim\Models\Company;
use Illuminate\Support\Facades\DB;
use Symfony\Component\HttpKernel\Exception\NotFoundHttpException;

class ExpenseRepository
{
    private $api_url;

    const API_GET = 'GET';
    const API_POST = 'POST';
    const API_PUT = 'PUT';

    function __construct()
    {
        $this->api_url = "http://xxx-xxx-xxx/api/v1/";
    }

    public function api_call($method, $uri, $request = NULL)
{
    try {

        $url=$this->api_url.$uri;
        $client = new Client(['base_uri' => $this->api_url]);
        $response = ($request) ? $client->request($method, $uri, $request) : $client->request($method, $uri);
    }
    catch (RequestException $e) {
        return $e;
    }
    return $this->formatResponseBody($response);
}

public static function formatResponseBody($response)
{
    $body = $response->getBody(true)->getContents();
    return json_decode($body);
}

public function addExpenseType($data)
{
    $uri = 'expense/types/add';
    $response = $this->api_call(self::API_POST, $uri, ['form_params' => $data]);
    return $response;

}

还有CompanyRepository.php

public function addExpenseType($company_id, $data)
    {
        $data['company_id'] = $company_id;
        $expense = new ExpenseRepository;
        $done = $expense->addExpenseType($data);
        if($done->status == 'success') {
          return true;
        }

        return true;
    }

我需要检查状态是否成功，但不断收到此错误：未定义的属性：GuzzleHttp \ Exception \ ConnectException :: $ status。请问我做错了什么？

Answer 1

此行引发异常：

catch (RequestException $e) {
    return $e;
}

并且您将返回异常。方法addExpenseType的返回值实际上是Guzzle抛出的异常。

抛出异常以查看错误。将您的代码更改为

catch (RequestException $e) {
        throw $e;
    }

Answer 2

更改formatResponseBody功能以添加$response->getBody()->rewind();

public static function formatResponseBody($response)
{
    $response->getBody()->rewind();
    $body = $response->getBody(true)->getContents();
    return json_decode($body);
}

在guzzle的旧版本中，它会在不重置指针之后读取完整的正文。使用rewind()将重置指针。如果这是您的问题的根源，rewind()将解决此问题。它已在新版本中得到解决。

未定义属性：GuzzleHttp \ Exception \ ConnectException :: $ status

2 个答案: