使用javascript排序JSON表

Question

我有这个简单的JSON表，其中元素需要按照alpabetical顺序按值排序，另一个按名称按顺序排序。有人可以给我一个例子我会怎么做才能理解它？

{

  "sortingTask": [

      {"sortAlpabeticallyByValue": [

      {"string":"äää"},

      {"string":"bee"},

      {"string":"aaa"},

      {"string":"öoöo"},

      {"string":"OöOö"},   

  ]},

      {"sortAlpabeticallyByName": [

      {"stringB":"testi1"},

      {"stringÄ":"testi2"},

      {"stringA":"testi3"}

  ]},

  {"sortAlpabetically": [

      "äää","bee","baa"

  ]}

  ]

}

Answer 1

You need to implement custom sort method using switch case. For comparison between two words you can use localeCompare

var data = { "sortingTask": [ {"sortAlpabeticallyByValue": [ {"string":"äää"}, {"string":"bee"}, {"string":"aaa"}, {"string":"öoöo"}, {"string":"OöOö"}, ]}, {"sortAlpabeticallyByName": [{"stringB":"testi1"}, {"stringÄ":"testi2"}, {"stringA":"testi3"} ]}, {"sortAlpabetically":[ "äää","bee","baa" ]}]};

data.sortingTask.forEach(function(obj){
  Object.keys(obj).forEach(function(k){
    switch(k){
      case 'sortAlpabeticallyByValue' :
        obj[k].sort(function(a,b){
          return a.string.localeCompare(b.string, undefined, { sensitivity: 'variant' });
        });
        break;
       case 'sortAlpabetically':
        obj[k].sort(function(a,b){
          return a.localeCompare(b, undefined, {sensitivity: 'variant'});
        });
        break;
       case 'sortAlpabeticallyByName':
        obj[k].sort(function(a,b){
          return Object.keys(a)[0].localeCompare(Object.keys(b)[0]);
        });
        break;
    }
  });
});
console.log(data);

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