Question

我有一个dict，其中包含一系列欧洲格式的日期(%d/%m/%Y)。我正在尝试重新格式化日期，以便它们采用美国格式(%m/%d/%Y)。每当我运行它时，都会发现以下错误：

ValueError: time data '2' does not match format '%m/%d/%Y'

任何人都知道我需要纠正什么？谢谢你的帮助！

from datetime import datetime
import time
from time import mktime


Transaction_Date=[
"23/08/2017",
"23/08/2017",
"21/08/2017",
"01/10/2017",
"19/08/2017",
"19/08/2017",
"18/08/2017",
"03/09/2017",
"27/09/2017",
"26/08/2017",
"03/10/2017",
"27/09/2017",
"27/03/2017",
"02/08/2017",
"20/08/2017",
"20/08/2017",
"20/08/2017",
"20/08/2017",
"20/08/2017",
"20/08/2017"]

for row in Transaction_Date:
    Transaction_Date = row[0]
    Transaction_Date = datetime.strptime(Transaction_Date,'%d/%m/%Y').strftime('%m/%d/%Y')
    print(Transaction_Date)

给出以下错误：

ValueError: time data '2' does not match format '%m/%d/%Y'

据我所知，日期格式是正确的，为什么系统说不同？

Answer 1

您的代码有2个错误： -

对收集和结果使用相同的名称（Transition_Date），您使用row[0]代替row

from datetime import datetime 
import time 
from time import mktime

Transaction_Date_Collection = [ "23/08/2017", "23/08/2017", "21/08/2017", "01/10/2017", "19/08/2017", "19/08/2017", "18/08/2017", "03/09/2017", "27/09/2017", "26/08/2017", "03/10/2017", "27/09/2017", "27/03/2017", "02/08/2017", "20/08/2017", "20/08/2017", "20/08/2017", "20/08/2017", "20/08/2017", "20/08/2017"]

for Transaction_Date in Transaction_Date_Collection: 
    Transaction_Date = datetime.strptime(Transaction_Date,'%d/%m/%Y').strftime('%m/%d/%Y')
    print(Transaction_Date)

Answer 2

您只需在循环中使用row，如下所示：

from datetime import datetime

Transaction_Dates = [
    "23/08/2017", "23/08/2017", "21/08/2017", "01/10/2017",
    "19/08/2017", "19/08/2017", "18/08/2017", "03/09/2017",
    "27/09/2017", "26/08/2017", "03/10/2017", "27/09/2017",
    "27/03/2017", "02/08/2017", "20/08/2017", "20/08/2017",
    "20/08/2017", "20/08/2017", "20/08/2017", "20/08/2017"]

for row in Transaction_Dates:
    print(datetime.strptime(row, '%d/%m/%Y').strftime('%m/%d/%Y'))

显示：

无法重新格式化日期

2 个答案: