Question

我搜索了论坛并在表单上尝试了几个结果，但我仍在努力解决以下问题。请你们给我以下建议：

Table 1: transactions
Rows: user_id, amount, received

Table 2: wallet
Rows: user_id, wallet_id

我需要加入2个结果：

结果1：

SELECT user_id, SUM(amount)FROM transactions WHERE received = '100' GROUP BY user_id

结果2：

SELECT * FROM transactions INNER JOIN wallet ON transactions.user_id = wallet.user_id

我要做的是通过使用user_id链接表2的wallet_id，并将其链接到表1中所有事务的user_id，其中= 100。我还需要在金额行上对结果求和。因此它将显示每个user_id的总数并将钱包链接到它。

我试过了：

SELECT user_id, SUM(amount)FROM transactions
INNER JOIN wallet ON transactions.user_id = wallet.user_id
WHERE received = '100' GROUP BY user_id

但它不起作用。请帮帮我们;-)

Answer 1

希望这有帮助。

SELECT user_id, wallet_id, SUM(amount)FROM transactions t
JOIN wallet w ON t.user_id = w.user_id
WHERE received = '100' GROUP BY user_id, wallet_id;

Answer 2

只需按user_id，wallet_id

添加分组即可

SELECT user_id, wallet_id, SUM(amount)FROM transactions
INNER JOIN wallet ON transactions.user_id = wallet.user_id
WHERE received = '100' GROUP BY user_id, wallet_id

Answer 3

如果您解释了代码失败的原因，那么修复起来会更容易。至少有一个错误是UINavigationController未定义。

一个简单的解决方案是使用.centerblock { position: absolute; left: 50%; top: 50%; /* <<< here you can set the value you want */ transform: translate ( -50%, -50%) }：

user_id

注意：如果USING是一个数字，则不要将SELECT user_id, SUM(t.amount) FROM transactions t INNER JOIN wallet w USING (user_id) WHERE t.received = '100' GROUP BY user_id;括在单引号中。

或者，您可以通过限定列名来编写查询 - 并且您应该对所有列进行限定：

received

如果您还想要100，请将其加入SELECT w.user_id, SUM(t.amount) FROM transactions t INNER JOIN wallet w ON w.user_id = t.user_id WHERE t.received = '100' GROUP BY w.user_id;和wallet_id：

SELECT

Answer 4

谢谢你们。你们好棒！！！！！这对我有用：

SELECT wallet_id，received，SUM（amount）FROM transaction INNER JOIN wallet ON transaction.user_id = wallet.uid WHERE received =＆＃39; 100＆＃39; GROUP BY wallet_id

内部加入MySQL表与表的总和

4 个答案: