Question

// If logged in, access mysql
$con =  mysqli_connect(DB_HOST, DB_USER, DB_PASS) or die(mysqli_error);

$user = mysqli_fetch_assoc(mysqli_query($con, "SELECT * FROM users WHERE username='" . $_SESSION['username'] . "'"));
echo '<ul>';

我的表名为users，我的用户名列为username

图片HERE

Answer 1

查询不正确删除会话中的两个点像这样查询

xor eax,eax

Answer 2

首先，您不要定义DB_NAME（数据库名称）

$con =  mysqli_connect(DB_HOST, DB_USER, DB_PASS,DB_NAME) or die(mysqli_error);


$userName = $_SESSION['username']; 
$stmt = mysqli_query($con,"SELECT * FROM users WHERE username ='$userName' ");
while( $user = mysqli_fetch_assoc($stmt) ){
  // if correct will pass to here
}

如果错误仍然存在从数据库中获取任何名称并使用参数

进行切换

mysqli_fetch_assoc（）期望参数1为mysqli_result，[duplicatione]中给出布尔值

2 个答案: