Question

我有下面的字符串，我想用逗号分隔。但这个钱也存在问题，其中也有逗号。我想要实现的目标;如果逗号后面有一个数字，请不要与该数字分开。我想用javascript做这个工作。

025056-03110,245056030,1，标准折扣，标准折扣， 15,940.00USD ，29/11 / 2017,1，

到目前为止我用千种组合尝试了什么;

[^ \，！\？] +

我期待的结果;

025056-03110
245056030
1
Standart Discount
Standart Discount
*15,940.00USD*
29/11/2017
1

Answer 1

此处的解决方案是将.match()与 this regex /(\d+,\d{3}[.]\d+\w+)|(\d+[\-][\d\w]+)|([\/\d\s\w]+)/g 一起使用，它将拆分所有元素并跳过带逗号的数字。

这应该是你的代码：

var str = "025056-03110,245056030,1,Standart Discount,Standart Discount,15,940.00USD,29/11/2017,1";
var matches = str.match(/(\d+,\d{3}[.]\d+\w+)|(\d+[\-][\d\w]+)|([\/\d\s\w]+)/g);

<强>演示：

var str = "025056-03110,245056030,1,Standart Discount,Standart Discount,15,940.00USD,29/11/2017,1";
var matches = str.match(/(\d+,\d{3}[.]\d+\w+)|(\d+[\-][\d\w]+)|([\/\d\s\w]+)/g);
console.log(matches);

Answer 2

let str = '025056-03110,245056030,1,Standart Discount,Standart Discount,15,940.00USD,29/11/2017,1,';
let price = str.match(/[A-Za-z],(\d+,?\d{1,3}\.\d{2}\w{3})/)[1];
let temp = price.replace(',', '|');

console.log(
  str.replace(price, temp)
    .split(',')
    .map(v => v.replace('|', ','))
    .filter(v => v)
);

Answer 3

也许你可以这样做：

(?:\d+,(?=\d+\.).+?(?=,)|[\w-\/.\s]+)

＆＃13;

var pattern = /(?:\d+,(?=\d+\.).+?(?=,)|[\w-\/.\s]+)/g;
var str = "025056-03110,245056030,1,Standart Discount,Standart Discount,15,940.00USD,29/11/2017,1,";
var matches = str.match(pattern);
for (var i = 0; i < matches.length; i++) {
    if (matches[i].indexOf('USD') !== -1) {
        matches[i] = "*" + matches[i] + "*";
    }
}
console.log(matches.join('\n'));

＆＃13;

Answer 4

而是match替代方案：\*[^*]*\*|[^\s,][^,]*

{{1}}

用逗号分割字符串，用钱问题

4 个答案: