Nodejs找到并返回特定元素？

Question

这是读取配置文件并返回数组我希望返回特定元素之类的细节，目前它的返回完整数组我想要简单的细节元素。

const lay = {
    key: null,
    information: {
        time: false,
        rate: false

    },
    details: {
        tip: false,
        edit: true

    }
};

我正在使用

transform() {
     return   conf.find((d) => {
            return d;
   });
}

Answer 1

const lay = {
  key: null,
  information: {
    time: false,
    rate: false
  },
  details: {
    tip: false,
    edit: true
  }
};

let transform = () => lay.details;

transform();

Answer 2

const lay = {
    key: null,
    information: {
        time: false,
        rate: false

    },
    details: {
        tip: false,
        edit: true

    }
};

function transform() {
     return  lay.details; //or lay['details']
}