UInt8 Array Swift to const char * C.

时间:2017-11-12 19:37:30

标签: c swift swift3

我有以下功能

public func encryptWithRSAKey(_ data: String, rsaKeyRef: SecKey, padding: SecPadding) -> [UInt8]? {

    let blockSize = SecKeyGetBlockSize(rsaKeyRef)
    var messageEncrypted = [UInt8](repeating: 0, count: blockSize)
    var messageEncryptedSize = blockSize

    var status: OSStatus!

    status = SecKeyEncrypt(rsaKeyRef, SecPadding.OAEP, data, data.count, &messageEncrypted, &messageEncryptedSize)

    if status != noErr {
        print("\(logClassName): Encryption Error!")
    }

    return messageEncrypted

}

输出是encryptedMessage = [9,43,128 ...] 128长度

我必须将结果发送到C函数

void STDCALL CpProxyAvOpenhomeOrgCredentials1BeginSet(THandle aHandle, const char* aId, const char* aUserName, const char* aPassword, uint32_t aPasswordLen, OhNetCallbackAsync aCallback, void* aPtr)
{
    CpProxyAvOpenhomeOrgCredentials1C* proxyC = reinterpret_cast<CpProxyAvOpenhomeOrgCredentials1C*>(aHandle);
    ASSERT(proxyC != NULL);
    Brh buf_aId(aId);
    Brh buf_aUserName(aUserName);
    Brh buf_aPassword;
    buf_aPassword.Set((const TByte*)aPassword, aPasswordLen);
    FunctorAsync functor = MakeFunctorAsync(aPtr, (OhNetFunctorAsync)aCallback);
    proxyC->BeginSet(buf_aId, buf_aUserName, buf_aPassword, functor);
}

将swift中的messageEncrypted编码为C中的const char * aPassword的方法是什么

2 个答案:

答案 0 :(得分:4)

C函数

void cfunc(const char* aPassword, uint32_t aPasswordLen);

的形式导入Swift
public func cfunc(_ aPassword: UnsafePointer<Int8>!, _ aPasswordLen: UInt32)

对于数组,withUnsafeBufferPointer()为您提供指向 (连续的)元素存储。由于签名不同 (Int8 vs UInt8),指针必须是&#34;反弹&#34;。例如:

let encryptedMessage: [UInt8] = [9, 43, 128]

encryptedMessage.withUnsafeBufferPointer {
    $0.baseAddress!.withMemoryRebound(to: Int8.self, capacity: encryptedMessage.count) {
        cfunc($0, UInt32(encryptedMessage.count))
    }
}

答案 1 :(得分:0)

我更喜欢这种方法:

如果我有:

let uint8ArrayVar:[UInt8]= [0,3,4,5]

如果我想通过我的c函数发送它,我只是这样做:

cfunc(uint8ArrayVar.map { Int8(bitPattern: $0) })