Question

我的架构是

var User = new mongoose.Schema({
    //general information
    name : {type:String},
    email : {type : String},
    number : {type : String},
    password : {type:String},
    //featured information
    path: { type: String},
    dob : {type:String},
    gender : {type : String},
    blood_group : {type:String},
    marital_status : {type : String}
});

module.exports = mongoose.model('user',User);

我想通过 -

更新一些细节

app.post('/contactinfo',function (req,res) {
    var name = req.body.name;
    var number = req.body.number;
    var email = req.body.email;
    User.update({_id : userID},{
        $push : {
            name : name,
            number : number,
            email : email
        }
    },{new : true },function (err,result) {
        if(err){
            console.log(err);
        }
        else{
            console.log(result);
            res.send({status : "success" , message : "Details updates"});
        }
    });
});

我没有在任何地方定义数组

但问题是更新时显示错误

{ MongoError: The field 'name' must be an array but is of type string in document {_id: ObjectId('5a0880e2d767e8131807e7f4')}

我被困在这里

请有人帮我解决此错误

Answer 1

您只需将vector<int> buildKMPtable(string word) { vector<int> kmp(word.size()); int j=0; for(int i=1; i < word.size(); ++i) { j = word[j] == word[i] ? j : kmp[j-1]; if(word[j] == word[i]) { kmp[i] = j + 1; ++j; } else { kmp[i] = j; } } return kmp; } bool repeatedSubstringPattern(string s) { auto kmp = buildKMPtable(s); if(kmp[s.size() -1] == 0) // Occurs when the string has no prefix with suffix ending at the last character of the string { return false; } int diff = s.size() - kmp[s.size() -1]; //Length of the repetitive pattern if(s.size() % diff != 0) //Length of repetitive pattern must be a multiple of the size of the string { return false; } // Check if that repetitive pattern is the only repetitive pattern. string word = s.substr(0, diff); int w_size = word.size(); for(int i=0; i < w_size; ++i) { int j = i; while(j < s.size()) { if(word[i] == s[j]) { j += w_size; } else { return false; } } } return true; }更改为$push即可。那就是它。

在mongodb中使用$ push时出错

1 个答案: