修改

Question

我正在从书中做教程，在24小时内自学django，在第1小时4分，我遇到了这个错误。

Traceback (most recent call last):

  File "C:\Python25\lib\site-packages\django\core\servers\basehttp.py", line 278, in run
    self.result = application(self.environ, self.start_response)

  File "C:\Python25\lib\site-packages\django\core\servers\basehttp.py", line 635, in __call__
    return self.application(environ, start_response)

  File "C:\Python25\lib\site-packages\django\core\handlers\wsgi.py", line 239, in __call__
    response = self.get_response(request)

  File "C:\Python25\lib\site-packages\django\core\handlers\base.py", line 67, in get_response
    response = middleware_method(request)

  File "C:\Python25\Lib\site-packages\django\middleware\common.py", line 56, in process_request
    if (not _is_valid_path(request.path_info) and

  File "C:\Python25\Lib\site-packages\django\middleware\common.py", line 142, in _is_valid_path
    urlresolvers.resolve(path)

  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 254, in resolve
    return get_resolver(urlconf).resolve(path)

  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 181, in resolve
    for pattern in self.url_patterns:

  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 205, in _get_url_patterns
    patterns = getattr(self.urlconf_module, "urlpatterns", self.urlconf_module)

  File "C:\Python25\Lib\site-packages\django\core\urlresolvers.py", line 200, in _get_urlconf_module
    self._urlconf_module = __import__(self.urlconf_name, {}, {}, [''])

  File "c:\projects\iFriends\..\iFriends\urls.py", line 17, in <module>
    (r'^admin/', include('django.contribute.admin.urls'))

TypeError: 'tuple' object is not callable

请有人帮帮我..

url.py

from django.conf.urls.defaults import *

####Uncomment the next two lines to enable the admin:
#### from django.contrib import admin
#### admin.autodiscover()

urlpatterns = patterns('',
    (r'^People/$', 'iFriends.People.views.index') ,
    (r'^admin/', include('django.contrib.admin.urls')), 
    # Example:
    # (r'^iFriends/', include('iFriends.foo.urls')),

    # Uncomment the admin/doc line below and add 'django.contrib.admindocs' 
    # to INSTALLED_APPS to enable admin documentation:
    # (r'^admin/doc/', include('django.contrib.admindocs.urls')),

    # Uncomment the next line to enable the admin:


)

Answer 1

你以某种方式将一些功能设置为一个元组。请修改问题并粘贴urls.py代码，以便我们指出错误。

我可以尝试疯狂猜测：

File "c:\projects\iFriends\..\iFriends\urls.py", line 17, in <module>
   (r'^admin/', include('django.contribute.admin.urls'))

这告诉我你错过了第16行的逗号，所以：

16. (r'^/', 'some_stuff....')      # <-- missed comma here
17. (r'^admin/', include('django.contribute.admin.urls'))

只需输入逗号即可。如果不是这样的话，我会发送我的水晶球来保持重要性。粘贴代码。

修改

好像你贴了urls.py作为答案。请修改问题并在其中粘贴urls.py。

无论如何，错误已经改变。你做了什么？在这个新错误中，找不到urls.py，所以也许你重命名了它？你改变了运行应用程序的方式吗？

您粘贴的文件不是正在运行的文件。你粘贴url.py并且django正在阅读urls.py吗？错误中的代码与您粘贴的代码不匹配！请粘贴正确的文件，即提供错误的文件，或者我们无法帮助。

TypeError：'tuple'对象不可调用

1 个答案:

修改