Question

我有一个json String如下所示，我使用反序列化到我的类对象但我不能，这是我的json。：

{
    "TraceId": "24bf6a01-5d8f-4959-9173-20600a04b738",
    "TransactionId": "AFC48AE50A076477C3E069296AC3F884",
    "ResponseTime": "1672",
    "DistanceUnits": "MI",
    "CurrencyType": "GBP",
    "xmlns:air": "http://www.travelport.com/schema/air_v42_0",
    "air:FlightDetailsList": {
            "air:FlightDetails": [
                {
                    "Key": "hx5kk+3R2BKAuFzqAAAAAA==",
                    "Origin": "DXB",
                    "Destination": "LHE",
                    "DepartureTime": "2017-12-10T13:55:00.000+04:00",
                    "ArrivalTime": "2017-12-10T17:55:00.000+05:00",
                    "FlightTime": "180",
                    "TravelTime": "180",
                    "Equipment": "320",
                    "OriginTerminal": "1",
                    "DestinationTerminal": "M"
                },
                {
                    "Key": "hx5kk+3R2BKAwFzqAAAAAA==",
                    "Origin": "LHE",
                    "Destination": "DEL",
                    "DepartureTime": "2017-12-20T12:15:00.000+05:00",
                    "ArrivalTime": "2017-12-20T14:10:00.000+05:30",
                    "FlightTime": "85",
                    "TravelTime": "690",
                    "Equipment": "ATR",
                    "OriginTerminal": "M",
                    "DestinationTerminal": "3"
                },
                {
                    "Key": "hx5kk+3R2BKAyFzqAAAAAA==",
                    "Origin": "DEL",
                    "Destination": "DXB",
                    "DepartureTime": "2017-12-20T20:25:00.000+05:30",
                    "ArrivalTime": "2017-12-20T22:45:00.000+04:00",
                    "FlightTime": "230",
                    "TravelTime": "690",
                    "Equipment": "788",
                    "OriginTerminal": "3",
                    "DestinationTerminal": "1"
                }
            ]
        }
}

所以我想转换成我的类 LowFareSearchRsp ，它的FlightDetails类也显示如下：

public class LowFareSearchRsp
{
    public string TraceId { get; set; }
    public string TransactionId { get; set; }
    public string ResponseTime { get; set; }
    public string DistanceUnits { get; set; }
    public string CurrencyType { get; set; }
    public string air { get; set; }
    public FlightDetailsList FlightDetailsList { get; set; }
}

public class FlightDetailsList
{
    public List<FlightDetails> FlightDetails { get; set; }
}

public class FlightDetails
{
    public string Key { get; set; }
    public string Origin { get; set; }
    public string Destination { get; set; }
    public DateTime Departure { get; set; }
    public DateTime ArrivalTime { get; set; }
    public string FlightTime { get; set; }
    public string TravelTime { get; set; }
    public string Equipment { get; set; }
    public string OriginTerminal { get; set; }
    public string DestinationTerminal { get; set; }
}

我正在使用NewtonSoft库将json反序列化为我的类对象，但收到以下错误：

{“无法反序列化当前的JSON对象（例如 {\“name \”：\“value \”}）进入类型 'System.Collections.Generic.List`1 [ParseSoapEnveloperReqRes.LowFareSearchRsp]' 因为该类型需要一个JSON数组（例如[1,2,3]）来反序列化正确。\ r \ n要修复此错误，请将JSON更改为JSON数组（例如[1,2,3]）或更改反序列化类型以使其正常 .NET类型（例如，不是整数的基本类型，不是集合类似于数组或List的类型，可以从JSON反序列化宾语。 JsonObjectAttribute也可以添加到类型中以强制它从JSON对象反序列化。\ r \ n''TraceId'，第2行，位置 12。“}

这是我的反序列化json字符串的代码：

var LowFareSearchRsps = JsonConvert.DeserializeObject<List<LowFareSearchRsp>>(jsonString);

我曾搜索过整个互联网，但无法找到解决方法。请帮助。感谢。

Answer 1

您的JSON不代表List<LowFareSearchRsp>，而是代表LowFareSearchRsp。

Answer 2

您的JSON字符串表示一个对象，而不是数组更改deserilize代码，如下所示：

var LowFareSearchRsps = JsonConvert.DeserializeObject<LowFareSearchRsp>(jsonString);

反序列化JSON不能与newtonsoft.json

2 个答案: