Question

我的网站上收到“网址未找到错误”。这些是我的文件：

myapp.urls：

url(r'^produkty/', include('supplement.urls', namespace='supplements')),

supplement.urls：

urlpatterns = [
url(r'^(?P<slug>[-\w]+)/$', SupplementDetailView.as_view(), name='detail'),
url(r'^$', SupplementListView.as_view(), name='list'),]

supplement.views：

class SupplementListView(ListView):
    def get_queryset(self):
        return Supplement.objects.all()

class SupplementDetailView(DetailView):
    queryset = Supplement.objects.all()

注意：queryset = Supplement.objects.all（）和get_queryset（self）：return Supplement.objects.all（）在SupplementDetailView中不起作用

supplement.models：

class Supplement(models.Model):
    name = models.CharField(blank=False, null=False, help_text=_("product's name"), max_length=50)
    price = models.IntegerField(blank=True, null=True)
    portion = models.CharField(max_length=100, blank=True, null=True, help_text=_("portion"))
    img = models.ImageField(default='kitchen/No-image-available.jpg', upload_to='products/', blank=True, null=True)
    description = RichTextField()
    contains = models.CharField(blank=True, null=True, max_length=3000, help_text=_("contains"))
    slug = models.SlugField(max_length=150, blank=True, null=True)

    def __str__(self):
        return self.name

    def get_absolute_url(self):
        return reverse('supplements:detail', kwargs={"slug": self.slug})

    class Meta:
        ordering = ['-name']
        verbose_name = _('supplement')
        verbose_name_plural = _('supplements')

def rl_pre_save_receiver(sender, instance, *args, **kwargs):
    if not instance.slug:
        instance.slug = unique_slug_generator(instance)


pre_save.connect(rl_pre_save_receiver, sender=Supplement)

SupplementListView和SupplementDetailView的模板放在BASE_DIR / supplement / templates / supplement中。

注意：SupplementDetailView就像一个魅力。它加载有关在url中传递的产品的信息（例如：myapp.pl/produkty/product-slug），但产品列表（myapp.pl/produkty）返回“未找到URL错误”

提前感谢您的帮助，我一直在努力解决这个错误。

Answer 1

我终于找到了答案：我的myapp.urls文件中有这个：

url(r'^', include('opinions.urls', namespace='home')),    
url(r'^produkty/', include('supplement.urls', namespace='supplements')),

所以每当我进入“myapp.pl/produkty/”时，Django都相信，“produkty”是一个意见模型的slu ..我切换了两个url模式（因此首先加载了namespace ='supplements'的模式），一切都很好。

网址未找到 - Django

1 个答案: