Question

我试图获取Button的背景图片并在if statement中使用它。并检查{1000}每1000毫升if statement。这是我的代码：

    final Button btn_1 = (Button)findViewById(R.id.button1);
    final Button btn_2 = (Button)findViewById(R.id.button2);
    final Button btn_3 = (Button)findViewById(R.id.button3);

    final ImageView a = (ImageView)findViewById(R.id.img1);
    final ImageView b = (ImageView)findViewById(R.id.img2);
    final ImageView c = (ImageView)findViewById(R.id.img3);


    class CheckCondition extends TimerTask {
        public void run() {
                if (btn_1.getResources().equals(R.drawable.ic_luncher) &&
                    btn_2.getResources().equals(R.drawable.ic_luncher) &&
                    btn_3.getResources().equals(R.drawable.ic_luncher)){

                a.setVisibility(View.VISIBLE);
                b.setVisibility(View.VISIBLE);
                c.setVisibility(View.VISIBLE);

            }
            else
            {
                a.setVisibility(View.INVISIBLE);
                b.setVisibility(View.INVISIBLE);
                c.setVisibility(View.INVISIBLE);
            }
        }
    }
    Timer timer = new Timer();

    timer.schedule(new CheckCondition(), 0, 1000);

但它只是不起作用。即使imageviews为真，if statement也始终不可见。我做错了什么？

Answer 1

它总是返回false，因为你正在比较错误的返回类型“Resource”（getResource）和“int”（drawable）。

Resources resources = btn_1.getResources();
int drawable = R.drawable.ic_luncher;

如果您正在寻找类似的可绘制比较而不是getConstantState可以帮助您进行验证。

Answer 2

或者您可以使用标签。

例如

button1.setTag("R.drawable.ic_luncher");
button2.setTag("R.drawable.ic_luncher");
button3.setTag("R.drawable.ic_luncher");

if (button1.getTag() == "R.drawable.ic_luncher" && button2.getTag() == "R.drawable.ic_luncher" && button3.getTag() == "R.drawable.ic_luncher") {

 a.setVisibility(View.VISIBLE);
 b.setVisibility(View.VISIBLE);
 c.setVisibility(View.VISIBLE);

}

如果带有计时器的语句不起作用

2 个答案: