Question

我是JAVA的新手（顺便提一下计算机编程）。以下程序检查输入是否为二进制。它应该提示用户重新输入整数，直到输入二进制数。但这个计划恰恰相反。如果输入是二进制的，它要求我重新输入整数，并且当输入非二进制时程序终止。我需要一个认真的帮助。Here is my output

    public static void main(String[] args) {

    int value, userValue;
    int binaryDigit = 0, notBinaryDigit = 0;

    Scanner scan = new Scanner(System.in);

    while (true) {
        System.out.println("Please enter positive integers: ");

        userValue = scan.nextInt();
        value = userValue;

        while (userValue > 0) {
            if ((userValue % 10 == 0) || (userValue % 10 == 1)) {
                binaryDigit++;
            } else {
                notBinaryDigit++;
            }

            userValue = userValue / 10;

        }

        if (notBinaryDigit > 0) {
            System.out.println(value + " is a not a Binary Number.");
            break;
        } else {
            System.out.println(value + " is  a  Binary Number.");

        }

    }
}

Answer 1

答案可能为时已晚。但是，如果使用该方法，则可以大大简化代码。

import java.util.Scanner;

public class MainClass {

    public static void main(String[] args) {
        Scanner scan = new Scanner(System.in);
        while (true) {
            System.out.println("Please enter positive integers: ");
            int userValue = scan.nextInt();
            if (isBinary(userValue)) {
                System.out.println(userValue + " is a Binary Number.");
                break;
            } else {
                System.out.println(userValue + " is  a not Binary Number.");
            }
        }
    }

    public static boolean isBinary(int input) {
        while (input > 0) {
            if ((input % 10 != 0) && (input % 10 != 1)) {
                return false;
            }
            input = input / 10;
        }
        return true;
    }
}

Answer 2

更改您的代码

来自这个

  if (notBinaryDigit > 0) {
        System.out.println(value + " is a not a Binary Number.");
        break;
    } else {
        System.out.println(value + " is  a  Binary Number.");

    }

到这个

 if (notBinaryDigit > 0) {
        System.out.println(value + " is a not a Binary Number.");
        notBinaryDigit--;
    } if(binaryDigit >0 {
        System.out.println(value + " is  a  Binary Number.");
 binaryDigit--;
  break;
    }

它会询问值并判断它是否为二进制，如果是二进制则终止

Answer 3

由于Scanner类而导致错误。您可以通过删除此类扫描程序类来运行程序并检查逻辑。

公共课测试{

public static void main(String []args){

    int value, userValue=34;
    int binaryDigit = 0, notBinaryDigit = 0;
    value = userValue;

    while (userValue > 0) {
        if ((userValue % 10 == 0) || (userValue % 10 == 1)) {
                binaryDigit++;
            } else {
                notBinaryDigit++;
            }

            userValue = userValue / 10;

        }

        if (notBinaryDigit > 0) {
            System.out.println(value + " is a not a Binary Number.");

        } else {
            System.out.println(value + " is  a  Binary Number.");

        }
}

}

提示用户重新输入整数，直到输入二进制数

3 个答案: