Question

我试图在不点击按钮的情况下自动进行串行连接。当gui加载时，应立即读取序列并按间隔刷新，而不使用鼠标触发任何按钮（即自动读入和更新）。

这有可能吗？请参阅下面的脚本和GUI ..

import schedule
import serial
import sys
from PyQt5 import uic, QtWidgets


qtCreatorFile = "gui.ui" 

Ui_MainWindow, QtBaseClass = uic.loadUiType(qtCreatorFile)

estudiantes = ['   ','    ','     ','    '] 

ser = serial.Serial('COM9', baudrate=9600, timeout=1)

class MyApp(QtWidgets.QMainWindow, Ui_MainWindow):
    def __init__(self):
        QtWidgets.QMainWindow.__init__(self)
        Ui_MainWindow.__init__(self)
        self.setupUi(self)
        self.Boton.clicked.connect(self.ingresos)
        #self.ingresos()

    def ingresos(self):

        dato = ser.readline().decode('ascii')

        #datos = (self.Box4.toPlainText())
        #dato = str(datos)
        estudiantes.insert(0,dato)
        estudiantes.pop()

        self.Box1.setText(estudiantes[0])
        self.Box2.setText(estudiantes[1])
        self.Box3.setText(estudiantes[2])
        self.Box4.setText(estudiantes[3])
        #self.Box1.setText("estudiantes")

# =============================================
        def job():
            # print("I'm working...")
            dato = ser.readline().decode('ascii')

            #datos = (self.Box4.toPlainText())
            #dato = str(datos)
            estudiantes.insert(0,dato)
            estudiantes.pop()

            self.Box1.setText(estudiantes[0])
            self.Box2.setText(estudiantes[1])
            self.Box3.setText(estudiantes[2])
            self.Box4.setText(estudiantes[3])
            #self.Box1.setText("estudiantes")

        # .......................    

        schedule.every(0.05).minutes.do(job)

        while True:
            schedule.run_pending()
            time.sleep(1)        

# .... Time definition ....
# 0.05 = 05 Seconds
# 0.50 = 50 Seconds
# 5.00 = 05 Minutes

# =============================================




if __name__ == "__main__":
    app =  QtWidgets.QApplication(sys.argv)
    window = MyApp()
    window.show()
    sys.exit(app.exec_())

PyQt5 GUI .ui文件是HERE ....

Answer 1

Qt中的一个基本规则是不应该从主要线程以外的线程更新GUI，这称为GUI线程。有几个选项，例如通过信号将数据发送到主线程，或使用QRunnable QThreadPool，如下所示：

代码：

qtCreatorFile = "gui.ui" 
Ui_MainWindow, QtBaseClass = uic.loadUiType(qtCreatorFile)
estudiantes = ['   ','    ','     ','    '] 

class SerialRunnable(QtCore.QRunnable):
    def __init__(self, w):
        QtCore.QRunnable.__init__(self)
        self.w = w
        self.ser = serial.Serial('COM9', baudrate=9600, timeout=1)

    def run(self):
        while True:
            dato = self.ser.readline().decode('ascii')
            if dato != "":
                QtCore.QMetaObject.invokeMethod(self.w, "setValues",
                                     QtCore.Qt.QueuedConnection,
                                     QtCore.Q_ARG(str, dato))
            QtCore.QThread.msleep(10)


class MyApp(QtWidgets.QMainWindow, Ui_MainWindow):
    def __init__(self):
        QtWidgets.QMainWindow.__init__(self)
        self.setupUi(self)
        runnable = SerialRunnable(self)
        QtCore.QThreadPool.globalInstance().start(runnable)

    @QtCore.pyqtSlot(str)
    def setValues(self, dato):
        estudiantes.insert(0,dato)
        estudiantes.pop()
        self.Box1.setText(estudiantes[0])
        self.Box2.setText(estudiantes[1])
        self.Box3.setText(estudiantes[2])
        self.Box4.setText(estudiantes[3])

PyQt5 - 自动化串行模块

1 个答案: