Question

我定义了一个函数，并尝试在URL中传递两个参数。

运行时会显示错误"not enough arguments for format string"

这是代码的 views.py

from django.shortcuts import render

# Create your views here.
from django.http import HttpResponse

def detail(request, question_id,choice):
    response="You're looking at question %s and choice %s."
    return HttpResponse(response % question_id , choice)

urls.py

from django.conf.urls import url

from . import views

urlpatterns = [
    url( r'^$', views.index , name='index' ) ,
    url( r'^(?P<question_id>[0-9])/(?P<choice>[0-9]+)/$', views.detail , name='detail' ) ,
]

当我通过网址时

http://127.0.0.1:8000/polls/1/2/

错误

TypeError at /polls/1/2/
not enough arguments for format string

如何解决？

Answer 1

尝试return HttpResponse(response % (question_id, choice))

Answer 2

使用%是在python中格式化字符串的旧方法。最好使用.format(..)，例如

response = "You're looking at question {} and choice {}.".format(question_id, choice)

所以你的代码将是

def detail(request, question_id,choice):
    response = "You're looking at question {} and choice {}.".format(question_id, choice)
    return HttpResponse(response)

有关详细信息，请查看pyformat.info。

无法在url中传递这两个参数

2 个答案: