Question

我正在尝试读取csv文件数据并使用类存储数据。我的变量没有直接在文件中定义，而是作为csv文件的输入。我想读取行Ground作为类Building_Storey的输入，并使用类方法from_st拆分行。但是我收到此错误too many values to unpack (expected 4)并显示错误消息missing 3 required positional arguments如果我在代码中早先拆分行Ground。似乎他将整行读作一个字符串，并给出整行的第一个参数。我不知道这段代码有什么问题。

输入csv文件：

TABLE;BuildingStorey;
GbxmlID;Name;Level;Internal Height;
F0;GroundFloor;0;3.7
F1;FirstFloor;4;3.7
F2;SecondFloor;16;8

代码：

with open('file.csv', 'r')as fp:
    copy = fp.readlines()
    print(copy)
    l = 0
    for line in copy:
        l = l + 1
        if l == 3:
            if 'GroundFloor' in line:
                Ground = line
                print(Ground) 

class Building_Storey:
    def __init__(self, GbxmlID, Name, Level, Internal_Height):

        self.GbxmlID = GbxmlID
        self.Name = Name
        self.Level = Level
        self.Internal_Height = Internal_Height

    @classmethod
    def from_st(cls, Story_st):
        GbxmlID, Name, Level, Internal_Height = Story_st.split(';')
        return cls(GbxmlID, Name, Level, Internal_Height)

Groundfloor = Building_Storey.from_st(Ground)  
print(Groundfloor.GbxmlID)
print(Groundfloor.Name)
print(Groundfloor.Level)
print(Groundfloor.Internal_Height)

输出应为：

  F0;GroundFloor;0;3.7;;;;;;;  # the line I want to read
  GroundFloor.GbxmlID = F0
  GroundFloor.Name = GroundFloor
  GroundFloor.Level = 0
  GroundFloor.Internal_Height = 3.7

Answer 1

你可以跳过前两个＆＃34;标题＆＃34;然后使用Python的csv库读取每一行，以自动将文本拆分为每行的值列表。如果列表包含4个条目，请使用*将值直接传递给您的类，以将每个列表元素作为参数传递给您的类：

import csv

class Building_Storey:
    def __init__(self, GbxmlID, Name, Level, Internal_Height):
        self.GbxmlID = GbxmlID
        self.Name = Name
        self.Level = Level
        self.Internal_Height = Internal_Height

with open('file.csv', newline='') as f_file:    
    csv_file = csv.reader(f_file, delimiter=';')
    header_1 = next(csv_file)
    header_2 = next(csv_file)

    for row in csv_file:
        if len(row) == 4:
            floor = Building_Storey(*row)
            print("ID: {}, Name: {}, Level: {}, Height: {}".format(floor.GbxmlID, floor.Name, floor.Level, floor.Internal_Height))

这会显示：

ID: F0, Name: GroundFloor, Level: 0, Height: 3.7
ID: F1, Name: FirstFloor, Level: 4, Height: 3.7
ID: F2, Name: SecondFloor, Level: 16, Height: 8

在类错误之外解压缩值

1 个答案: