matplotlib数据点之间的间距相等

Question

我正在尝试使用x轴绘制一些数据，显示数据点之间的等距间距。

代码：

def newline_or_execute_outer(shell):
    def newline_or_execute(event):
        """When the user presses return, insert a newline or execute the code."""
        b = event.current_buffer
        d = b.document

        if b.complete_state:
            cc = b.complete_state.current_completion
            if cc:
                b.apply_completion(cc)
            else:
                b.cancel_completion()
            return

        # If there's only one line, treat it as if the cursor is at the end.
        # See https://github.com/ipython/ipython/issues/10425
        if d.line_count == 1:
            check_text = d.text
        else:
            check_text = d.text[:d.cursor_position]
        status, indent = shell.input_splitter.check_complete(check_text + '\n')

        if not (d.on_last_line or
                d.cursor_position_row >= d.line_count - d.empty_line_count_at_the_end()
                ):
            b.insert_text('\n' + (' ' * (indent or 0)))
            return

        if (status != 'incomplete') and b.accept_action.is_returnable:
            b.accept_action.validate_and_handle(event.cli, b)
        else:
            b.insert_text('\n' + (' ' * (indent or 0)))
    return newline_or_execute

外观如何： 我希望它看起来如何：

因此每两个相邻点之间的距离相等。

Answer 1

因此，您的图表似乎仅用于表示目的。 x轴上的数字不需要在比例上。要绘制此图，您必须创建一个x轴列表，该列表实际上是按比例缩放的，只需用sizes列表的元素替换其标签即可。以下代码显示了如何执行此操作

#!/usr/bin/env python
from matplotlib import pyplot as plt

sizes = [1400, 1600, 1700, 1875, 1100, 1550, 2350, 2450, 1425, 1700]
prices = [245, 312, 279, 308, 199, 219, 405, 324, 319, 255]

plt.ylim([0, 500])
plt.xlabel("sizes")
plt.ylabel("prices")

x = [a for a in range(len(sizes))]
plt.scatter(x,prices)
plt.xticks(x, sizes)
plt.show()