Question

我一直在使用宏定义将一组文件复制到不同的位置和FTP服务器。但是复制似乎很慢，所以我想使用7z压缩捆绑包并将所有内容作为单个文件复制到FTP中。可以用7z完成吗？我的amcrodef在其下面工作：

<macrodef name="copyimages">
  <attribute name="todir"/>
  <sequential>
    <copy todir="@{todir}" overwrite="true" failonerror="false">
      <fileset dir="${build.output.dir}">
                  <include name="logs/*${build.id}*armv5*scan2.html"/>
                  <include name="logs/*${build.id}*main.ant.log"/>
        <include name="logs/*${build.id}*bom.xml"/>
        <include name="logs/compile/*${build.id}*.*"/>
        <include name="logs/cone/*${build.id}*.*"/>
        <include name="logs/post/*${build.id}*.*"/>
        <include name="logs/roms/*${build.id}*.*"/>
        <include name="**/*${build.id}_codescanner/**"/>
      </fileset>
    </copy>
  </sequential>
</macrodef>


<copyimages todir="${publish.ssdoci.dir}/${env.version}.${build.number}"/>

Answer 1

如果您不是特别关注7z，那么您可以使用Zip Task。

你可以尝试这样的事情而不是<copy></copy ......

<zip destfile ="@{destfile}">
  <fileset dir="${build.output.dir}">
    <include name="logs/*${build.id}*armv5*scan2.html"/>
    <include name="logs/*${build.id}*main.ant.log"/>
    <include name="logs/*${build.id}*bom.xml"/>
    <include name="logs/compile/*${build.id}*.*"/>
    <include name="logs/cone/*${build.id}*.*"/>
    <include name="logs/post/*${build.id}*.*"/>
    <include name="logs/roms/*${build.id}*.*"/>
    <include name="**/*${build.id}_codescanner/**"/>
  </fileset>
</zip>

<copyimages destfile="${publish.ssdoci.file}-${env.version}.${build.number}"/>

Answer 2

7zip没有任务 - ＆lt; zip＆gt;无法使用密码存档。因此我的解决方案是

<target name="zip" depends="dist">
    <exec executable="C:\Program Files\7-Zip\7z.exe">
        <arg value="a" />                         <!--archive-->
        <arg value="-pMyPasswordt" />             <!-- password -->
        <arg value="-r" />                        <!-- recursiv -->
        <arg value="C:\temp\2012-06-29\${programName}.zip" />  <!-- destination -->
        <arg value="${jarFile}" />                <!-- files to archive -->
    </exec>
</target>

Answer 3

我猜使用带有“exec”的7z.exe是最好的选择。

以下是语法：

C：\ Program Files \ 7-Zip＆gt; 7z.exe a -t7z c：\ temp \ test.7z c：\ temp * .txt

*此命令将来自c：\ temp的所有.txt文件存档为“test.7z”

干杯！

Answer 4

这里有一个7z ant任务：http://www.pharmasoft.be/7z/

虽然没有测试，但该网站似乎已经过时了。

Answer 5

根据apache.org，支持7z 从osdir.com开始，有关于实施sevenz任务的评论与使用zip的方式相同

使用maven？

<artifactId>maven-antrun-plugin</artifactId>
<dependencies>
  <dependency>
    <groupId>org.apache.commons</groupId>
    <artifactId>commons-compress</artifactId>
    <version>1.8</version>
  </dependency>
  <dependency>
    <groupId>org.apache.ant</groupId>
    <artifactId>ant-compress</artifactId>
    <version>1.4</version>
  </dependency>

蚂蚁

<taskdef resource="org/apache/ant/compress/antlib.xml" classpathref="maven.plugin.classpath"/>
<sevenz destfile ="my.7z">
  <fileset dir="${build.output.dir}">
    <include name="logs/*${build.id}*armv5*scan2.html"/>
    <include name="logs/*${build.id}*main.ant.log"/>
    <include name="logs/*${build.id}*bom.xml"/>
    <include name="logs/compile/*${build.id}*.*"/>
    <include name="logs/cone/*${build.id}*.*"/>
    <include name="logs/post/*${build.id}*.*"/>
    <include name="logs/roms/*${build.id}*.*"/>
    <include name="**/*${build.id}_codescanner/**"/>
  </fileset>
</sevenz>
<un7z src="my.7z" dest="unpack" />

在ANT中将7z合并到macrodef中

5 个答案: