为什么php mysqli_prepare select query返回null?

时间:2017-11-11 13:42:38

标签: php

我使用php从数据库中获取数据,但我遇到了问题。

首先,它是从数据库获取数据的php文件。

{"response":[{"ID":null,"postWriter":null,"postContent":null,"postDate":null,"postPic":null,"postLike":null,"postComments":null,"postLocation":null,"profilePic":null,"postGatherDate":null,"postGatherLocation":null,"postGatherTime":null},{"ID":null,"postWriter":null,"postContent":null,"postDate":null,"postPic":null,"postLike":null,"postComments":null,"postLocation":null,"profilePic":null,"postGatherDate":null,"postGatherLocation":null,"postGatherTime":null},{"ID":null,"postWriter":null,"postContent":null,"postDate":null,"postPic":null,"postLike":null,"postComments":null,"postLocation":null,"profilePic":null,"postGatherDate":null,"postGatherLocation":null,"postGatherTime":null}]}

>

然而,它返回如下。它具有正确的数据数,但其值均为空。我该如何解决这个问题?

access_token

0 个答案:

没有答案