是否可以在Applescript中获取Illustrator画板的名称?
此脚本完美无缺,直到我尝试获取画板的名称:
tell application "Adobe Illustrator"
tell document 1
set artboards_count to count of artboards
set c to 1
repeat while c <= artboards_count
log index of artboard c as text
log artboard rectangle of artboard c as text
log name of artboard c as text -- this line fails
set c to c + 1
end repeat
end tell
end tell
行log name of artboard c as text
失败 - 其他一切正常。
消息是:
Adobe Illustrator got an error: Can’t get name of artboard 1 of document 1. (-1728)
知道为什么?
设置名称也失败了,BTW。但是,如果我这样做
tell application "Adobe Illustrator"
tell document 1
return properties of artboard 1
end tell
end tell
我得到了(为了澄清而添加了回车):
artboard rectangle:0.0, 0.0, 841.889999999999, -595.280000000001,
ruler PAR:1.0, show center:false, show cross hairs:false,
show safe areas:false, ruler origin:0.0, 0.0, name:Artboard 1,
container:document 1, best type:reference, default type:reference,
class:artboard, index:1
从哪个人会认为属性name
应该在那里。
答案 0 :(得分:0)
name属性是只读的,因此一旦画板存在就无法更改它。而且,即使您可以获取画板的属性,但是如果您只想定位特定的画板,也无法将其转换为字符串。但是尽管如此,我还是偶然发现了一种方法。假设您有几个画板,并且想要定位名为“ Squash this”的画板。操作方法如下:
Tell application "Adobe Illustrator"
tell current document
set artCount to number of artboards
repeat with i from 1 to artCount
set artProp to get properties of artboard i
try
set propString to artProp as string --this will fail
on error
set errorDisp to text of result --this captures the text of the error
set errorDispText to errorDisp as string --changes the text to a ¬
searchable string
end try
if errorDispText contains "quash" then
display notification "errorDispText" --oddly enough, this displays just ¬
the artboard name
exit repeat
end if
end repeat
end tell
end tell
答案 1 :(得分:0)
最好的解决方法是强制。获取从Artboard属性返回的记录并将其强制转换为列表。因此,记录中的name属性将成为列表中的第七项。下面的代码将获取Artboard的尺寸,名称和索引,并将它们放入列表中,以供以后在脚本中使用。
希望这会有所帮助!
tell application "Adobe Illustrator"
set artboardDetails to {}
tell front document
set allArtboards to every artboard
repeat with i from 1 to count of allArtboards
set thisArtboard to item i of allArtboards
set thisArtboardProps to properties of thisArtboard
set thisArtboardDimensions to artboard rectangle of thisArtboardProps
set thisArtboardIndex to index of thisArtboardProps
--WORKAROUND
set thisArtboardPropsCoerce to thisArtboardProps as list
set thisArtboardName to item 7 of thisArtboardPropsCoerce
set the end of artboardDetails to {thisArtboardName, thisArtboardIndex, thisArtboardDimensions}
end repeat
end tell
end tell
(*
--WORKAROUND
The following is a workaround for error returned from:
set anArtboardName to the name of anArtboard -- this line will not return a result, just errors out
BUT WE NEED TO WATCH OUT FOR THE COERCED LIST!
So, we have to coerce the properties record of artboard to a list first
WEIRD I KNOW!
The coercion then changes the record of 11 items to a list of 12 items
set anArtboardProps to properties of anArtboard as list
set anArtboardName to item 7 of anArtboardProps
NOW LETS MATCH UP THE COERCION ITEMS
The first lines are from the record properties, and the second lines are from the coerced to list versions.
01. artboard rectangle:{0.0, 768.0, 1366.0, 0.0},
01. {0.0, 768.0, 1366.0, 0.0},
02. ruler PAR:1.0,
02. 1.0,
03. show center:false,
03. false,
04. show cross hairs:false,
04. false,
05. show safe areas:false,
05. false,
06. ruler origin:{0.0, 0.0},
06. {0.0, 0.0},
07. name:"Artboard 1",
07. "Artboard 1",
08. container:document 1,
08. document 1,
09. best type:reference,
09. reference,
10. default type:reference,
10. reference,
11. index:1
11. artboard,
12. NULL - nothing in the record
12. 1 - so this line is the index of the artboard
*)
答案 2 :(得分:0)
这是我的解决方法。每次编译时,“ bal9类”都会消失,因此每次都必须复制/粘贴,但这是可行的。是的,«class bAl9»将变为“ name”,并且下次将无法正确编译。谢谢Adobe!
tell application "Adobe Illustrator"
tell document 1
repeat with x in (every artboard)
log index of x as text
log artboard rectangle of x as text
log «class bAl9» of x as text -- artboard's name property = «class bAl9»
end repeat
end tell
end tell
画板的 name 属性为读/写,一旦获得窍门,就很容易以这种方式重命名画板。
编辑:对于列表中的循环,我总是使用在x中重复l 语句。快速又聪明。
答案 3 :(得分:0)
Stu 的答案是我找到的最好的答案。将记录强制列在列表中非常棒——我什至不知道你能做到这一点。我的代码是:
repeat with i from 1 to the (count of AllArtBoards)
set ThisArtBoard to item i of AllArtBoards
set ThisArtBoardName to item 7 of ((properties of ThisArtBoard) as list)
set the end of AllArtBoardNames to ThisArtBoardName
end repeat