Question

美好的一天我目前正致力于一个看起来像财富之轮的项目。我有这个适配器，我想知道是否有可能有一个计数器将数据发送到另一个类，如果它在其他最底层请帮助谢谢

package com.forteza.answerme.adapter;

公共类GridViewSuggestAdapter扩展了BaseAdapter {

private List<String> suggestSource;
private Context context;
private Level2 level2;

public GridViewSuggestAdapter(List<String> suggestSource, Context context, Level2 level2) {
    this.suggestSource = suggestSource;
    this.context = context;
    this.level2 = level2;

}

@Override
public int getCount() {
    return suggestSource.size();
}

@Override
public Object getItem(int position) {
    return suggestSource.get(position);
}

@Override
public long getItemId(int position) {
    return position;
}

@Override
public View getView(final int position, View convertView, ViewGroup parent) {
    Button button;

    if(convertView == null)
    {
        if(suggestSource.get(position).equals("null"))
        {

            button = new Button(context);
            button.setLayoutParams(new GridView.LayoutParams(85,85));
            button.setPadding(8,8,8,8);
            button.setBackgroundColor(Color.DKGRAY);

        }
        else
        {
            button = new Button(context);
            button.setLayoutParams(new GridView.LayoutParams(85,85));
            button.setPadding(8,8,8,8);
            button.setBackgroundColor(Color.DKGRAY);
            button.setTextColor(Color.YELLOW);
            button.setText(suggestSource.get(position));
            button.setOnClickListener(new View.OnClickListener() {

                @Override
                public void onClick(View v) {
                    int error=0;
                    //If correct answer contains character user selected
                    if(String.valueOf(level2.answer).contains(suggestSource.get(position)))
                    {
                        char compare = suggestSource.get(position).charAt(0); // Get char

                        for(int i =0;i<level2.answer.length;i++)
                        {
                            if(compare == level2.answer[i])
                                Common.user_submit_answer[i] = compare;
                        }

                        //Update UI
                        GridViewAnswerAdapter answerAdapter = new GridViewAnswerAdapter(Common.user_submit_answer,context);
                        level2.gridViewAnswer.setAdapter(answerAdapter);
                        answerAdapter.notifyDataSetChanged();

                        //Remove from suggest source
                        level2.suggestSource.set(position,"null");
                        level2.suggestAdapter = new GridViewSuggestAdapter(level2.suggestSource,context,level2);
                        level2.gridViewSuggest.setAdapter(level2.suggestAdapter);
                        level2.suggestAdapter.notifyDataSetChanged();
                    }
                    else // else
                    {
                        //Remove from suggest source
                        level2.suggestSource.set(position,"null");
                        level2.suggestAdapter = new GridViewSuggestAdapter(level2.suggestSource,context,level2);
                        level2.gridViewSuggest.setAdapter(level2.suggestAdapter);
                        level2.suggestAdapter.notifyDataSetChanged();







                    }
                }
            });
        }
    }
    else
        button = (Button)convertView;
    return button;

}

}

Answer 1

在该适配器上创建一个接口，并在满足条件时触发该侦听器。在您的其他活动上实施该界面，并在您的活动中的已实施方法中执行某些操作。

适配器中的计数器，并在条件

1 个答案: