Question

我的连接到url（xml）文件时遇到问题，并创建了java对象。到目前为止，我无法连接到我的链接，因为＆＃34;服务器返回了HTTP响应代码：415为URL＆＃34;

我的链接：http://services.odata.org/V3/Northwind/Northwind.svc/Employees

我的代码（不完整，但抛出异常）：

 package logic;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.parsers.ParserConfigurationException;

import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;
import org.xml.sax.SAXException;

public class XMLReader {

    public static void main(String[] args) throws IOException, ParserConfigurationException, SAXException {
        //JsonObject requestJson = new JsonObject();
        String url = "http://services.odata.org/V3/Northwind/Northwind.svc/Employees";
        URL myurl = new URL(url);
        HttpURLConnection con = (HttpURLConnection)myurl.openConnection();
        con.setDoOutput(true);
        con.setDoInput(true);

        con.setRequestProperty("Content-Type", "application/xml; charset=utf-8");
        con.setRequestProperty("Accept", "application/xml");
        con.setRequestProperty("Method", "GET");

        InputStream xml = con.getInputStream();

        DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
        DocumentBuilder db = dbf.newDocumentBuilder();
        Document doc = db.parse(xml);

        doc.getDocumentElement().normalize();
}

Answer 1

请 con.setRequestProperty（＆＃34; Accept＆＃34;，＆＃34; application / xml＆＃34;）; 至 con.setRequestProperty（＆＃34;接受＆＃34;，＆＃34; * / xml＆＃34;）;

Answer 2

在我的情况下，我将“application/xml”更改为“text/xml”并且它起作用了。

服务器返回HTTP响应代码：415为URL（java / xml）

2 个答案: