Question

为什么iter_rows总是说must be str, not int？我只是想将lst值传递给min_row和max_row。

from openpyxl import load_workbook
from itertools import islice

wb = load_workbook('xyz.xlsx')
ws1 = wb['Sheet1']

lst = ['2','2']
limit = 2

for i in islice(lst,limit):
    row = ws1.iter_rows(min_row=i,max_row=i)

我已尝试将here发送给iter_rows min_row max_row的想法，但我得到的错误与Worksheet object has no attribute

相同

引用错误

 line 509, in iter_rows
 max_row += row_offset

Answer 1

iter_rows方法期望min_row和max_row输入参数是整数。所以试试这个：

from openpyxl import load_workbook

from itertools import islice

wb = load_workbook('xyz.xlsx')
ws1 = wb['Sheet1']

lst = [2,2]
limit = 2

for i in islice(lst,limit):
    row = ws1.iter_rows(min_row=i,max_row=i)

注意：您可以通过使用命令iter_rows或help(ws1.iter_rows)查询其文档字符串来获取help(openpyxl.worksheet.worksheet.Worksheet.iter_rows)方法的完整使用说明。在docstring中，您可以找到说明：

:param min_row: smallest row index (1-based index)
:type min_row: int

:param max_row: smallest row index (1-based index)
:type max_row: int

带循环的Openpyxl iter_rows（min_row，max_row）

1 个答案: