Question

我有以下代码：

def check(onen,twon,threen,fourn,fiven):
while ((onen != twon) and (onen != threen) and (onen != fourn) and (onen != fiven)):
    return onen
else:
    onen = random.randint(1,45)

我想问一下如何做到这一点：

def check(onen,twon,threen,fourn,fiven):
while ((onen != twon) and (onen != threen) and (onen != fourn) and (onen != fiven)):
    return onen
else:
    onen = random.randint(1,45)
        (check the condition on while again)

我想做这个循环：如果条件为假，检查并再次检查，直到它为真。

Answer 1

你基本上寻找的是一个do-while循环。 Python没有do-while循环，但您可以轻松模拟一个：

def something():
    while True:
        # ...
        # perform some task
        if [condition]:
            return [result]

所以在这里你必须填写[condition]来检查结果是否令人满意，[result]是你想要返回的。只要不满足条件，Python就会进行另一个循环。

示例：

假设您要查询用户输入，可以使用以下命令执行此操作：

def something(): while True: try: x = int(input('Enter a number')) except ValueError: x = None if x is not None: return x

所以在这里我们将继续查询一个数字，直到它是一个有效数字。

当然，我们有时可以一起折叠任务和条件检查。在这里，我们可以将上述程序转换为：

def something(): while True: try: return int(input('Enter a number')) except ValueError: pass

Answer 2

好像你倒退了。试试这个：

jQuery(function($){


var $content = $('.projects');
var $loader = $('#more_posts');
var ppp = 4;
var offset = $('.projects').find('.project').length;

$loader.on( 'click', load_ajax_posts );

function load_ajax_posts() {
    if ( !($loader.hasClass('post_loading_loader') || $loader.hasClass('post_no_more_posts')) ) {
        $.ajax({
            type: 'POST',
            dataType: 'html',
            url: screenReaderText.ajaxurl,
            data: {
                'ppp': ppp,
                'offset': offset,
                'action': 'mytheme_more_post_ajax'
            },
            beforeSend : function () {
                $loader.addClass('post_loading_loader').html( screenReaderText.loading );
            },
            success: function (data) {
                var $data = $(data);
                if ($data.length) {
                    var $newElements = $data.css({ opacity: 0 });



                    $content.append($newElements);

                    $content.isotope( 'appended', $newElements );

                    $content.isotope( 'reloadItems' );  // https://isotope.metafizzy.co/methods.html#reloaditems

                    $content.isotope('layout'); // https://isotope.metafizzy.co/methods.html#layout


                    $newElements.animate({ opacity: 1 });

                    $loader.removeClass('post_loading_loader').html(screenReaderText.loadmore);

                } else {

                    $loader.removeClass('post_loading_loader').addClass('post_no_more_posts').html(screenReaderText.noposts);

                }
            },
            error : function (jqXHR, textStatus, errorThrown) {
                $loader.html($.parseJSON(jqXHR.responseText) + ' :: ' + textStatus + ' :: ' + errorThrown);
                console.log(jqXHR);
            },
        });
    }

    offset += ppp;
    return false;

}


});

对于您的具体示例：

while not condition:
    change condition
return that

或更短：

def check(onen, twon, threen, fourn, fiven):
    while not ((onen != twon) and (onen != threen) and (onen != fourn) and (onen != fiven)):
        onen = random.randint(1,45)
    return onen

或多更短，没有循环（但只适用于小范围）：

def check(onen, twon, threen, fourn, fiven):
    while onen in (twon, threen, fourn, fiven):
        onen = random.randint(1,45)
    return onen

但请注意，这些都不会改变函数之外的def check(onen, twon, threen, fourn, fiven): return random.choice([x for x in range(1, 46) if x not in (twon, threen, fourn, fiven)])的值（当然，除非你做onen）。

Answer 3

从更新到你的问题，似乎你只需要反思时间的感觉来得到你想要的东西：

def condition(onen, twon, threen, fourn, fiven):
    return ((onen != twon) and (onen != threen) and (onen != fourn) and (onen != fiven))

def check(onen, twon, threen, fourn, fiven):
    while not condition(onen, twon, threen, fourn, fiven):
        onen = random.randint(1,45)
    return onen

Answer 4

你也可以试试这个：

_Pragma("prolog(foo, \"#MCPROLG MAIN=(YES,16,132)\"")

Answer 5

def something(): 
    while(condition): 
        return that 
    else: 
        return this
        something() # just callback the function

你也可以删除else语句并只回调当前函数

而/ Else重新检查条件和循环

5 个答案: