Question

所以我有以下JSON块：

b'{"data":[{"categories":[{"id":"IAB3","label":"Business","parent":"IAB3","score":"0.223819028028717559","confident":true}],"url":"megatel.de"}]}'

我只需要一个包含第一个标签字段内容的字符串。

Answer 1

以下代码段将输出返回为Business

import json
data = json.loads('{"data":[{"categories":[{"id":"IAB3","label":"Business","parent":"IAB3","score":"0.223819028028717559","confident":true}],"url":"megatel.de"}]}')
print(data['data'][0]['categories'][0]['label'])

如果你有更多这样的数据，你可以迭代data变量并通过在两个地方用迭代器替换0索引来获得所需的结果。

例如，如果json有点如下

{"data":
        [
            {"categories":
                [
                    {"id":"IAB3",
                    "label":"Business",
                    "parent":"IAB3",
                    "score":"0.223819028028717559",
                    "confident":true}
                ],
            "url":"megatel.de"
            },
            {"categories":
                [
                    {"id":"IAB3",
                    "label":"Business",
                    "parent":"IAB3",
                    "score":"0.223819028028717559",
                    "confident":true}
                ],
                "url":"megatel.de"
            }
        ]
}

您可以使用以下脚本来获得类似的输出。

for entry in data['data']:
    for categories in entry['categories']:
        print categories['label']

Answer 2

x = b'{"data":[{"categories":[{"id":"IAB3","label":"Business","parent":"IAB3","score":"0.223819028028717559","confident":true}],"url":"megatel.de"}]}' 
(x.split('"label":')[1]).split(",")[0][1:-1]
>>'Business'

Answer 3

如果您也可以尝试使用正则表达式方法：

td

我如何只获得JSON答案的一个特定方面

3 个答案: