Question

新手在这里。使用Google API附近搜索。我有问题将封装数据发送到封闭，已经填充了附近信息的表，但是当我尝试将placeID信息发送到闭包以获取详细信息时，它给我零。

这里我得到placeID和附近，然后用places数组填充tableView。 Class Place位于单独的swift文件中，函数downloadPlaceID位于ViewController内。

 class Place {

    var placeId: String!
    var vicinity: String!

    var _placeId: String {
        if placeId == nil {
            placeId = ""
        }
        return placeId
    }

    var _vicinity: String {
        if vicinity == nil {
            vicinity = ""
        }
        return vicinity
    }


    init( place: [String:Any]) {

        if let ids = place["id"] as? String {
            self.placeId = ids

        }

        if let vicinities = place["vicinity"] as? String {
            self.vicinity = vicinities

        }

    }

}


func downloadPlaceID (completed: @escaping DownloadComplete) {

        let placeURL = URL(string: nearbyURL)

        Alamofire.request(placeURL!).responseJSON { (response) in
            let result = response.result

            if let dictionary = result.value as? [String:Any] {
                if let results = dictionary["results"] as? [[String:Any]] {

                    if let status = dictionary["status"] as? String  {
                        if status == "OK" {
                            for obj in results {
                                place = Place(place: obj)
                                // here i get all the placeID's
                                places.append(place)
                            }
                        }
                    }
                }
            }
            completed()
        }
    }

然后我尝试获取详细信息，我放置了地址ID：

   func downloadDetails( input: String, completed: DownloadComplete) {

        let details = "\(detailsBaseURL)\(detailsPlaceId)\(input)\(detailsKey)\(detailsSearchAPIKey)"
        print(placeID)

        Alamofire.request(details).responseJSON { response in
            let result = response.result

            if let dictionary = result.value as? [String:Any] {

                if let result = dictionary["result"] as? [String:Any] {

                    if let phoneNumber = result["formatted_phone_number"] as? String {
                        self.phone = phoneNumber
                        print(self.phone!)
                    }

                    if let  geometry = result["geometry"] as? [String:Any] {
                        if let location = geometry["location"] as? [String:Any] {
                            if let latitude = location["lat"] as? Double {
                                self.lat = latitude
                                print(self.lat!)
                            }
                            if let longitude = location["lng"] as? Double {
                                self.lng = longitude
                                print(self.lng!)
                            }
                        }
                    }

                    if let openingHours = result["opening_hours"] as? [String:Any] {
                        if let openNow = openingHours["open_now"] as? Bool {
                            self.workHours = openNow
                             print(self.workHours!)
                        }
                    }
                }
            }
        }
    }

以下是我试图用来获取详细信息的viewDidLoad中的代码。

  override func viewDidLoad() {
super.viewDidLoad()


downloadPlaceID {
    detail.downloadDetails(input: place.placeId, completed: {

    })
}



}

Answer 1

应该是“place_id”而不是“id”

<xsl:stylesheet version="3.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:xs="http://www.w3.org/2001/XMLSchema" 

xmlns:pi="urn:com.workday/picof">
        <xsl:output method="text"/>
            <xsl:template match="pi:Payroll_Extract_Employees/pi:company">
                <xsl:variable name="test">
                <xsl:text>pi:employee/pi:name</xsl:text>
            </xsl:variable>
                <xsl:variable name="names" as="element(name)*">
                <xsl:evaluate xpath="$test" context-item="."/>
            </xsl:variable>
                <xsl:value-of select="$names"/>
            </xsl:template>
    </xsl:stylesheet>

在封闭中管理封装数据

1 个答案: