Question

我正在尝试将两个单独的查询合并为一个。我正在将它们用于jaspersoft报告工作室。第一个查询的输出是有关指定日期范围之间的表中条目的详细信息。第二个查询的输出包含第一个查询的一些输出量以及它自己的参数。他们分开工作很好。

所以我甚至不确定是否可以将这些组合到一个单一查询中。

查询1：

 SELECT
 `alarminfo`.`condition_id`,
 `alarminfo`.`landscape_h`,
 `landscape`.`domain_name`,
 `model`.`model_name`,
 `alarminfo`.`set_time`,
 `alarminfo`.`clear_time` ,
 `alarminfo`.`alarm_key`,
 `alarmtitle`.`title`,
 `alarminfo`.`ack_time`,
 `alarminfo`.`set_troubleticket_id`,
 `alarminfo`.`first_assigned_time`,
 `alarmcondition`.`condition_name`,
 TIMESTAMPDIFF(SECOND,alarminfo.set_time ,alarminfo.clear_time) seconds_to_clear,
  TIMESTAMPDIFF(SECOND,alarminfo.set_time ,'2017-09-01 00:00:00.0') alerttime
 FROM  alarminfo
 INNER JOIN landscape ON (alarminfo.landscape_h=landscape.landscape_h)
 INNER JOIN alarmtitle ON (alarminfo.alarm_title_id=alarmtitle.alarm_title_id)
 INNER JOIN model ON (alarminfo.model_key=model.model_key)
 INNER JOIN alarmcondition on (alarminfo.condition_id=alarmcondition.condition_id)
  where
 ((alarminfo.set_time>='2017-09-01 00:00:00.0' AND alarminfo.set_time<'2017-09-30 23:59:59.0') AND
   (alarminfo.clear_time>='2017-09-01 00:00:00.0' AND alarminfo.clear_time<'2017-09-30 23:59:59.0') AND
   (alarmcondition.condition_name IN ('Critical', 'Major', 'Minor')) AND
   (TIMESTAMPDIFF(SECOND,alarminfo.set_time ,alarminfo.ack_time)>60*15)


 )
   order by `alarminfo`.`set_troubleticket_id`DESC , `alarminfo`.`ack_time` , `alarminfo`.`set_time` , `alarminfo`.`landscape_h`, `alarminfo`.`condition_id`

查询2：

select
count(*) 'Total alarms',
  sum(case when ack_time is not null then 1 else 0 end) as 'total acknowledged',
  sum(case when (TIMESTAMPDIFF(SECOND,alarminfo.set_time ,alarminfo.ack_time)<60*15) then 1 else 0 end) as 'Total acknowledged within 15min',
  sum(case when (TIMESTAMPDIFF(SECOND,alarminfo.set_time ,alarminfo.ack_time)>60*15) then 1 else 0 end) as 'Total acknowledged after 15min'
 FROM  alarminfo
 where
 alarminfo.set_time>='2017-09-01 00:00:00.0' AND alarminfo.set_time<'2017-09-30 23:59:59.0'

这就是我试图将它们合并在一起的方式：

SELECT
 `alarminfo`.`condition_id`,
 `alarminfo`.`landscape_h`,
 `landscape`.`domain_name`,
 `model`.`model_name`,
 `alarminfo`.`set_time`,
 `alarminfo`.`clear_time` ,
 `alarminfo`.`alarm_key`,
 `alarmtitle`.`title`,
 `alarminfo`.`ack_time`,
 `alarminfo`.`set_troubleticket_id`,
 `alarminfo`.`first_assigned_time`,
 `alarmcondition`.`condition_name`,
 TIMESTAMPDIFF(SECOND,alarminfo.set_time ,alarminfo.clear_time) seconds_to_clear,
  TIMESTAMPDIFF(SECOND,alarminfo.set_time ,'2017-09-01 00:00:00.0') alerttime
 FROM  alarminfo
 INNER JOIN landscape ON (alarminfo.landscape_h=landscape.landscape_h)
 INNER JOIN alarmtitle ON (alarminfo.alarm_title_id=alarmtitle.alarm_title_id)
 INNER JOIN model ON (alarminfo.model_key=model.model_key)
 INNER JOIN alarmcondition on (alarminfo.condition_id=alarmcondition.condition_id)
  where
 ((alarminfo.set_time>='2017-09-01 00:00:00.0' AND alarminfo.set_time<'2017-09-30 23:59:59.0') AND
   (alarminfo.clear_time>='2017-09-01 00:00:00.0' AND alarminfo.clear_time<'2017-09-30 23:59:59.0') AND
   (alarmcondition.condition_name IN ('Critical', 'Major', 'Minor')) AND
   (TIMESTAMPDIFF(SECOND,alarminfo.set_time ,alarminfo.ack_time)>60*15)


 )

count(*) 'Total alarms',
  sum(case when ack_time is not null then 1 else 0 end) as 'total acknowledged',
  sum(case when (TIMESTAMPDIFF(SECOND,alarminfo.set_time ,alarminfo.ack_time)<60*15) then 1 else 0 end) as 'Total acknowledged within 15min',
  sum(case when (TIMESTAMPDIFF(SECOND,alarminfo.set_time ,alarminfo.ack_time)>60*15) then 1 else 0 end) as 'Total acknowledged after 15min'
 FROM  alarminfo
 where
 alarminfo.set_time>='2017-09-01 00:00:00.0' AND alarminfo.set_time<'2017-09-30 23:59:59.0'
)

   order by `alarminfo`.`set_troubleticket_id`DESC , `alarminfo`.`ack_time` , `alarminfo`.`set_time` , `alarminfo`.`landscape_h`, `alarminfo`.`condition_id`

遗憾的是，这不起作用。有人知道如何合并它们吗？

Answer 1

使用第一个查询的输出作为第二个查询的输入。因为，第一个查询中已经包含第二个查询的where子句所以我们可以省略它。

选择
     count（*）＆＃39; Total alarms＆＃39;，
       总和（ack_time不为空的情况，然后是1，否则为0结束）为＆＃39;总确认＆＃39;，
       sum（（TIMESTAMPDIFF（SECOND，R.set_time，R.ack_time）＆lt; 60 * 15）然后1或0结束时的情况）＆＃39;在15分钟内确认总数＆＃39;，
       sum（（TIMESTAMPDIFF（SECOND，R.set_time，R.ack_time）> 60 * 15）然后1或0结束时的情况）＆＃39; 15分钟后确认总数＆＃39;
      FROM（选择
     alarminfo。condition_id，
     alarminfo。landscape_h，
     landscape。domain_name，
     model。model_name，
     alarminfo。set_time，
     alarminfo。clear_time，
     alarminfo。alarm_key，
     alarmtitle。title，
     alarminfo。ack_time，
     alarminfo。set_troubleticket_id，
     alarminfo。first_assigned_time，
     alarmcondition。condition_name，
     TIMESTAMPDIFF（第二，alarminfo.set_time，alarminfo.clear_time）seconds_to_clear，
     TIMESTAMPDIFF（第二，alarminfo.set_time，＆＃39; 2017-09-01 00：00：00.0＆＃39;）alerttime
     来自alarminfo
     INNER JOIN landscape ON（alarminfo.landscape_h = landscape.landscape_h）
     INNER JOIN警报标志ON（alarminfo.alarm_title_id = alarmtitle.alarm_title_id）
     INNER JOIN模型ON（alarminfo.model_key = model.model_key）
     INNER JOIN报警条件打开（alarminfo.condition_id = alarmcondition.condition_id）
     其中
     （（alarminfo.set_time＆gt; =＆＃39; 2017-09-01 00：00：00.0＆＃39; AND alarminfo.set_time＆lt;＆＃39; 2017-09-30 23：59：59.0＆＃39;）和
     （alarminfo.clear_time＆gt; =＆＃39; 2017-09-01 00：00：00.0＆＃39; AND alarminfo.clear_time＆lt;＆＃39; 2017-09-30 23：59：59.0＆＃39;）AND <登记/>      （alarmcondition.condition_name IN（＆＃39; Critical＆＃39;，＆＃39; Major＆＃39;，＆＃39; Minor＆＃39;））和
     （TIMESTAMPDIFF（SECOND，alarminfo.set_time，alarminfo.ack_time）＆gt; 60 * 15）
     ）
     按alarminfo排序。set_troubleticket_id DESC，alarminfo。ack_time，alarminfo。set_time，alarminfo。landscape_h ，alarminfo。condition_id
     ）作为R

结合2个单独的SQL查询

1 个答案: