Question

我正在努力在条件下从JSON收集值。基础数据和预期数据如下。我想收集与key1和key2的值相同的ID。收集数据的关键是当每个元素的key1和key2相同时，我想得到每个键的值。我很抱歉这个令人困惑的解释。

我必须在Google Apps脚本中使用此脚本。所以请注意我不能使用ECMAScript6。

基础JSON

var data = [
    {id: "id_A", key1: "value1", key2: "value2"},
    {id: "id_B", key1: "value2", key2: "value3"},
    {id: "id_C", key1: "value3", key2: "value4"},
    {id: "id_D", key1: "value2", key2: "value3"},
    {id: "id_E", key1: "value2", key2: "value3"},
    {id: "id_F", key1: "value3", key2: "value4"},
    {id: "id_G", key1: "value1", key2: "value2"},
    {id: "id_H", key1: "value4", key2: "value5"}
]

预期结果

var result = [
    {id: ["id_A", "id_G"], key: ["value1", "value2"]},
    {id: ["id_B", "id_D", "id_E"], key: ["value1", "value2", "value3"]},
    {id: ["id_C", "id_F"], key: ["value1", "value2", "value3", "value4"]},
    {id: ["id_H"], key: ["value1", "value2", "value3", "value4", "value5"]}
]

我当前的剧本

function convertJSON(){
  var json = [
      {id: "id_A", key1: "value1", key2: "value2"},
      {id: "id_B", key1: "value2", key2: "value3"},
      {id: "id_C", key1: "value3", key2: "value4"},
      {id: "id_D", key1: "value2", key2: "value3"},
      {id: "id_E", key1: "value2", key2: "value3"},
      {id: "id_F", key1: "value3", key2: "value4"},
      {id: "id_G", key1: "value1", key2: "value2"},
      {id: "id_H", key1: "value4", key2: "value5"}
  ];

  var sorted = json.sort(function(i, j){
    if (i.key1 < j.key1){
      return -1;
    }
    if (i.key1 > j.key1){
      return 1;
    }
    return 0;
  });

  var result = [];
  var id = [];
  var key = [];
  var key1 = "";
  var key2 = "";
  for (var i = 0; i < sorted.length; i++){ 
    if (i > 0) {
      if (key1 == sorted[i].key1 && key2 == sorted[i].key2){
        id.push(sorted[i].id);
        key.push(sorted[i].key1);
        key.push(sorted[i].key2);
      } else {
        var key = key.filter(function(e, i, ar) {
          return ar.indexOf(e) == i;
        });
        result.push({id: id, key: key});
        var id = [];
        var key = [];    
        var key1 = sorted[i].key1;
        var key2 = sorted[i].key2;
        id.push(sorted[i].id);
        key.push(sorted[i].key1);
        key.push(sorted[i].key2);
      }
    } else {
      var key1 = sorted[i].key1;
      var key2 = sorted[i].key2;
      id.push(sorted[i].id);
      key.push(sorted[i].key1);
      key.push(sorted[i].key2);
    }
  }
  console.log(JSON.stringify(result));

// result is
// [
//   {"id":["id_A","id_G"],"key":["value1","value2"]},
//   {"id":["id_B","id_D","id_E"],"key":["value2","value3"]},
//   {"id":["id_C","id_F"],"key":["value3","value4"]}
// ]
}

非常感谢您的时间和建议。

Answer 1

这个示例脚本怎么样？请将此视为几个答案之一。我认为有更有效的方法。当我看到你的问题时，起初我想到了3个部分。所以我分成3个部分来检索结果。

检索第一步和最后一步。
- 检索的第一步和最后一步用作分析楼梯的参考点。
Analize stairs。
- 按顺序检索整个步骤。
汇总ID和密钥。

我确认此示例脚本适用于GAS。

示例脚本：

var data = [
    {id: "id_A", key1: "value1", key2: "value2"},
    {id: "id_B", key1: "value2", key2: "value3"},
    {id: "id_C", key1: "value3", key2: "value4"},
    {id: "id_D", key1: "value2", key2: "value3"},
    {id: "id_E", key1: "value2", key2: "value3"},
    {id: "id_F", key1: "value3", key2: "value4"},
    {id: "id_G", key1: "value1", key2: "value2"},
    {id: "id_H", key1: "value4", key2: "value5"},
];

// 1. Retrieve first and last steps.
var firststep, laststep;
for (var i in data) {
  var chk1 = data[i].key1;
  var chk2 = data[i].key2;
  var f1 = true;
  var f2 = true;
  for (var j in data) {
    if (data[j].key2 == chk1) f1 = false;
    if (data[j].key1 == chk2) f2 = false;
  }
  if (f1) firststep = data[i];
  if (f2) laststep = data[i];
}

// 2. Analize stairs.
var stairs = [];
stairs.push(firststep);
var key1 = firststep.key1;
var key2 = firststep.key2;
while (key2 != laststep.key2) {
  var temp = {};
  for (var i in data) {
    if (data[i].key1 == key2) {
      if (!temp[data[i].key1]) {
        stairs.push(data[i]);
        temp[data[i].key1] = true;
      }
    }
  }
  key2 = stairs[stairs.length - 1].key2;
}

// 3. Summarize IDs and Keys.
var result = [];
var key = [];
for (var i in stairs) {
  var id = [];
  if (!~key.indexOf(stairs[i].key1)) key.push(stairs[i].key1);
  key.push(stairs[i].key2);
  for (var j in data) {
    if (data[j].key1 == stairs[i].key1 && data[j].key2 == stairs[i].key2) {
      id.push(data[j].id);
    }
  }
  result.push({id: id.slice(), key: key.slice()});
}

// When you use GAS, you can see the result at Stackdriver.
// Or please use Logger.log(JSON.stringify(result, null, "\t"))
console.log(JSON.stringify(result, null, "\t"));

我的理解是否正确？如果我误解了你的问题，请告诉我。我想修改。

在条件下从JSON收集值

1 个答案:

示例脚本：