在下面的代码片段中,由于某种原因,eror的值不在FOR循环之外。
eror = 0 ;
for (i=0; i<n; i++)
{
predict = intercept + (slope * data[i][0]) ;
printf("In the FOR loop eror = %lf\n", eror) ;
eror +=(data[i][1] - predict) ;
}
printf("Out of FOR loop eror = %lf\n", eror) ;
部分输出是......
In the FOR loop eror = -0.028400
In the FOR loop eror = -0.011216
In the FOR loop eror = 0.012196
In the FOR loop eror = 0.019527
In the FOR loop eror = 0.024293
In the FOR loop eror = 0.021309
In the FOR loop eror = 0.013337
Out of FOR loop eror = -0.000000
任何人都可以解释为什么FOR循环中有一个值,但是一旦变量eror退出FOR循环就没有了吗?
答案 0 :(得分:0)
尝试:
eror = 0 ;
for (i=0; i<n; i++)
{
predict = intercept + (slope * data[i][0]) ;
eror +=(data[i][1] - predict) ;
printf("In the FOR loop eror = %lf\n", eror) ;
}
printf("Out of FOR loop eror = %lf\n", eror) ;