Question

嗨，我正在尝试在一个Cell中使用Paginator，Paginator工作得很严格，但是单元格模板中的PaginatorHelper不起作用。

我正在使用CakePhp 3.5

这是我的代码

的src /查看/小区/ FinderCell.php

namespace App\View\Cell;
use Cake\View\Cell;
use Cake\Datasource\Paginator;
class FinderCell extends Cell {

    public function display() {
        $this->loadModel('Pokemon');
        $paginador = new Paginator();

        $pokemons = $paginador->paginate(
            $this->Pokemon->find()
        );

        $this->set(compact('pokemons'));
    }
}

的src /模板/小区/搜索/ display.ctp

<?php 
foreach ($pokemons as $pokemon) :
 ?>
<div class="tipo form large-2 medium-2 columns content">
    <?php echo $this->Html->image($pokemon->pokemon_image) ?>
</div>
<?php endforeach; ?>

<div class="paginator">
    <ul class="pagination">
        <?= $this->Paginator->prev('<< Anterior') ?>
        <?= $this->Paginator->numbers() ?>
        <?= $this->Paginator->next('Siguiente >>') ?>
    </ul>
    <p><?= $this->Paginator->counter() ?></p>
</div>

我明白了

Answer 1

如果你想使用帮助器，那么你需要使用分页参数填充请求对象，这是paginator组件通常会为你做的事情：

// ...

$pagingParams = $paginator->getPagingParams();

$this->set(compact('pokemons', 'pagingParams'));

或paginator helper，它依次设置请求对象上的参数：

$this->Paginator->options(['paging' => $pagingParams]);

String pasteText = null;
Object pasteObj = Display.getInstance()
                    .getPasteDataFromClipboard();   

if (pasteObj instanceof CharSequence) {
    pasteText = pasteObj.toString();
}

另见

的 API > \Cake\Datasource\PaginatorInterface::getPagingParams()

的 API > \Cake\View\Helper\PaginatorHelper::options()

在CakePhp 3中使用PaginatorHelper

1 个答案: