dplyr编程:unquote-splicing导致overcope错误,包括complete()和nesting()

时间:2017-11-09 21:22:06

标签: r dplyr rlang

所以我开始尝试进入dplyr编程的精彩世界。我正在尝试编写一个接受data.frame,目标列和任意数量的分组列的函数(使用所有列的裸名称)。然后,该函数将基于目标列对数据进行分箱,并计算每个箱中的条目数。我想为原始data.frame()中存在的分组变量的每个组合保留一个单独的bin大小,所以我使用complete()和nesting()函数来执行此操作。这是我正在尝试做的一个例子以及我遇到的错误:

library(dplyr)
library(tidyr)

#Prepare test data
set.seed(42)
test_data =
    data.frame(Gene_ID = rep(paste0("Gene.", 1:10), times=4),
               Comparison = rep(c("WT_vs_Mut1", "WT_vs_Mut2"), each=10, times=2),
               Test_method = rep(c("T-test", "MannWhitney"), each=20),
               P_value = runif(40))

#Perform operation manually
test_data %>% 
    #Start by binning the data according to q-value
    mutate(Probability.bin = cut(P_value,
                                 breaks = c(-Inf, seq(0.1, 1, by=0.1), Inf),
                                 labels = c(seq(0.0, 1.0, by=0.1)),
                                 right = FALSE)) %>% 
    #Now summarize the results by bin.
    count(Comparison, Test_method, Probability.bin) %>% 
    #Fill in any missing bins with 0 counts
    complete(nesting(Comparison, Test_method), Probability.bin,
             fill=list(n = 0))

#Create function that accepts bare column names
bin_by_p_value <- function(df,
                           pvalue_col, #Bare name of p-value column
                           ...) {      #Bare names of grouping columns

    #"Quote" column names so they are ready for use below
    pvalue_col_name <- enquo(pvalue_col)
    group_by_cols <- quos(...)

    #Perform the operation
    df %>% 
        #Start by binning the data according to q-value
        mutate(Probability.bin = cut(UQ(pvalue_col_name),
                                     breaks = c(-Inf, seq(0.1, 1, by=0.1), Inf),
                                     labels = c(seq(0.0, 1.0, by=0.1)),
                                     right = FALSE)) %>% 
        #Now summarize the results by bin.
        count(UQS(group_by_cols), Probability.bin) %>% 
        #Fill in any missing bins with 0 counts
        complete(nesting(UQS(group_by_cols)), Probability.bin,
                 # complete(nesting(UQS(group_by_cols)), Probability.bin,
                 fill=list(n = 0))
}

#Use function to perform operation
test_data %>% 
    bin_by_p_value(P_value, Comparison, Test_method)

当我手动执行操作时,一切正常。当我使用该函数时,它会因此错误而失败:

  

overscope_eval_next(overscope,expr)出错:       对象'比较'未找到

我已将问题缩小到函数中的以下代码:

complete(nesting(UQS(group_by_cols)), Probability.bin...

如果我删除了对nesting()的调用,代码将在没有错误的情况下执行。但是,我想保持功能,我只使用原始数据中存在的分组变量的组合,然后获得所有可能的组合,所以我可以填写所有缺少的分档。基于错误名称和失败的地方,我的猜测是这是一个范围/环境问题,我真的应该在nesting()中为分组变量使用不同的环境,因为它包含在对complete()的调用中。但是,我已经足够dplyr编程,我不知道该怎么做。

我尝试通过将分组列合并为一个列,然后将该联合列用作complete()的输入来解决此问题。这让我可以按照我想要的方式执行complete()操作,同时避免使用nesting()函数。但是,当我想分回原始的分组列时,我遇到了麻烦,因为我不知道如何将一个quosures列表转换为一个字符向量(separate()的“into”参数所需)。以下是代码片段,用于说明我在说什么:

        #Fill in any missing bins with 0 counts
        unite(Merged_grouping_cols, UQS(group_by_cols), sep="*") %>% 
        complete(Merged_grouping_cols, Probability.bin,
                 fill=list(n = 0)) %>%
        separate(Merged_grouping_cols, into=c("What goes here?"), sep="\\*")

以下是相关版本信息:R版本3.4.2(2017-09-28),tidyr_0.7.2,dplyr_0.7.4

我很感激任何变通方法,但我想知道我在做什么,这是以错误的方式摩擦complete()和嵌套()。

1 个答案:

答案 0 :(得分:1)

  • {{}} 使用 curl-curly pvalue_col
  • 将点 (...) 直接传递给 count
  • ensyms 中使用 !!!nesting
bin_by_p_value <- function(df,
                           pvalue_col, #Bare name of p-value column
                           ...) {      #Bare names of grouping columns
  
  #Perform the operation
  df %>% 
    #Start by binning the data according to q-value
    mutate(Probability.bin = cut({{pvalue_col}},
                                 breaks = c(-Inf, seq(0.1, 1, by=0.1), Inf),
                                 labels = c(seq(0.0, 1.0, by=0.1)),
                                 right = FALSE)) %>% 
    #Now summarize the results by bin.
    count(..., Probability.bin) %>% 
    #Fill in any missing bins with 0 counts
    complete(nesting(!!!ensyms(...)), Probability.bin,   fill=list(n = 0))
}

test_data %>% bin_by_p_value(P_value, Comparison, Test_method)

# A tibble: 44 x 4
#   Comparison Test_method Probability.bin     n
#   <chr>      <chr>       <fct>           <dbl>
# 1 WT_vs_Mut1 MannWhitney 0                   1
# 2 WT_vs_Mut1 MannWhitney 0.1                 1
# 3 WT_vs_Mut1 MannWhitney 0.2                 0
# 4 WT_vs_Mut1 MannWhitney 0.3                 1
# 5 WT_vs_Mut1 MannWhitney 0.4                 1
# 6 WT_vs_Mut1 MannWhitney 0.5                 1
# 7 WT_vs_Mut1 MannWhitney 0.6                 0
# 8 WT_vs_Mut1 MannWhitney 0.7                 0
# 9 WT_vs_Mut1 MannWhitney 0.8                 1
#10 WT_vs_Mut1 MannWhitney 0.9                 4
# … with 34 more rows

如果手动调用的输出存储在res中,则测试输出。

identical(res, test_data %>% bin_by_p_value(P_value, Comparison, Test_method))
#[1] TRUE