Question

花了很多时间没有成功。我正在使用Alamofire对后端服务器进行HTTP POST，这需要一些参数来提供请求。我成功点击了服务器，但是服务器响应500表示没有发送参数？

我已尝试过大多数SO解决方案（更改编码类型，将参数设置为NSDict等），但没有成功。

非常感谢任何帮助。

PS其Swift3与Alamofire 4

代码：

let params: [String: String] = ["deviceID": "Some device ID",
                  "email": "email","password": "password","userid": "1234",
                  "username":"gordon"]

let request_params: Parameters = ["LoginUser" : params]

let url = "https://myserver/LogIn" as String

Alamofire.request(url, method: .post, parameters: request_params, encoding:  URLEncoding.default, headers: [
        "Content-Type": "application/x-www-form-urlencoded"
        ]).responseString { (response:DataResponse<String>) in

        switch(response.result) {
        case.success(let data):
            print("success",data)
            print(response.response)
        case.failure(let error):
            print("Failed!",error)

        }

    }

更新

以下是POST的正文，看起来这就是问题所在：

Alamofire POST正文（来自上面的代码） - （LoginUser％5BdeviceID％5D = 12345＆安培; LoginUser％5Bemail％5D =戈登％40test.com＆安培; LoginUser％5Buserid％5D = 00000000-0000-0000-0000-000000000000＆安培; LoginUser％5Bpassword％5D = testPassword＆安培; LoginUser％5Busername％5D =戈登）

应该是（忽略编码值）：

这是一个功能性帖子 - LoginUser =％7B％22deviceID％22％3A％22％22％2C％22email％22％3A％22gordon％40test.com％22％2C％22password％22％3A％22testPassword％22％2C％22userid％22％3A ％2200000000-0000-0000-0000-000000000000％22％2C％22username％22％3A％22gordon％22％7D

正如您所看到的，Alamofire帖子似乎将LoginUser连接到每个属性的开头？还缺少LoginUser = at ?? ??

Answer 1

尝试使用JSONEncoding.default代替URLEncoding.default

Answer 2

好的，所以我使用下面的代码工作，会非常有兴趣了解这是否是发布参数的最有效方法？

let params: NSMutableDictionary? = ["deviceID": "someDeviceID",
                  "email": "emailAddress","password": "aSecret","userid": "12345",
                  "username":"gordon"]
    let url = "https://serverAdrress" as String

    let data = try! JSONSerialization.data(withJSONObject: params!, options: JSONSerialization.WritingOptions.prettyPrinted)
    let json: NSString! = NSString(data: data, encoding: String.Encoding.utf8.rawValue)

    let request_params: Parameters = ["LoginUser" : json as Any]

    Alamofire.request(url, method: .post, parameters: request_params, encoding:  URLEncoding.httpBody, headers: [
        "Content-Type": "application/x-www-form-urlencoded"
        ]).responseString { (response:DataResponse<String>) in

        switch(response.result) {
        case.success(let data):
            print("success",data)
            print(NSString(data: (response.request?.httpBody)!, encoding: String.Encoding.utf8.rawValue))
            print(response.response)
        case.failure(let error):
            print("Not Success",error)

        }

    }

Alamofire 4在POST中缺少参数

2 个答案: