Question

我创建了一个移动应用程序来扫描QR-CODE，其中嵌入了各种信息。其中一个信息是日期。

以前版本的QR-CODE与日期格式有所变化。之前的日期格式为mm / dd，新版本为yy-MM-dd。

我能够让它扫描新版本的标签或旧标签，但不能同时扫描两者。我需要让它识别机器人类型。我不确定是否有办法使用if语句识别旧格式并将其转换为新格式。

以下是使用新标签的工作代码示例。

(function(){
'use strict';

var app = angular.module('Controllers', []);
var baseUrl = 'https://apps.laticrete.com/LSCWebApiService/lscapi/';

app.controller('BarcodeCtrl', ['$scope', '$state', '$stateParams', '$http', 'alertsManager', '$timeout', 'localStorageService', '$cordovaBarcodeScanner', '$cordovaGeolocation', '$filter',
    function($scope, $state, $stateParams, $http, alertsManager, $timeout, localStorageService, $cordovaBarcodeScanner, $cordovaGeolocation, $filter) {
        var SessionId = localStorageService.get('SessionId');

        // Get GeoLocation
        $cordovaGeolocation
            .getCurrentPosition()
            .then(function(position) {
                $scope.lat = position.coords.latitude;
        $scope.long = position.coords.longitude;
            });

document.addEventListener("deviceready", function() {
    $scope.scanMaterial = function() {


        $cordovaBarcodeScanner
            .scan()
            .then(function(result) {

                var codeArray = result.text.split(',');
                $scope.SKU = codeArray[1].replace("I:", "").trim();
                $scope.ControlNumber = codeArray[0].replace("W:", "").trim(); 
                //$scope.ManufactureDate = codeArray[2].replace("MFG:", "").trim();
                $scope.ManufactureDate = codeArray[2].replace("MFG:", "20").replace(/(\d{4})(\d{2})(\d{2})/, "$1-$2-$3").trim();

                $scope.BatchCode = codeArray[3].replace("B:", "").trim();

                var dataObj = {
                    SessionId: SessionId,
                    JobId: $stateParams.JobId,
                    ManufactureDate: $scope.ManufactureDate, 
                    BatchCode: $scope.BatchCode,
                    SKU: $scope.SKU,
                    ControlNumber: $scope.ControlNumber,
                    CreatedClient: new Date(),
                    Latitude: $scope.lat,
                    Longitude: $scope.long, 
                    Product: { Id : 1}
                };

                $http.post(baseUrl + 'Material/PostNewMaterial', dataObj)
                    .success(function() {
                        alertsManager.addAlert('Success: You have successfully added material.', 'alert-success');
                        $state.go('^');
                    }).error(function(dataObj) {
                        alertsManager.addAlert('Failure Meesage: ' + JSON.stringify({dataObj:dataObj}), 'alert-danger');
                    });
                    $timeout(function(){
                        alertsManager.clearAlerts();
                    }, 5000);

            }, function(error) {
                console.log("An error has happened " + error);
            });
    };
}, false);


}]);

}）（）;

我要求帮助的部分代码是$ scope.ManufactureDate

提前谢谢你。

Answer 1

检查代码是否与其中一种格式匹配，如果匹配，则相应地解析。

if (codeArray[2].match(/MFG:\d+-\d+-\d+/) !== null) {
    /* The format is of 'MFG:000-000-000', \d+ matches 1..n numbers */
    ...
}

或者你可以将它们组合成一个正则表达式：

let matches = codeArray[2].match(/MFG:(20(\d{2})-\d{2}-\d{2})|(\d{2}/\d{2}))/);

请参阅String.prototype.match

如果在Javascript中不正确，则更改日期格式

1 个答案: