Question

美好的一天，我需要将过去的变量发布到其他文件

  }
        $.ajax({
            url: 'emps.php',
            type: 'POST', // GET or POST
             data: {"sucursal":$("#suc").val()},
            success: function(data) { // data is the response from your php script
                // This function is called if your AJAX query was successful
              alert(data);
            },
            error: function() {
                // This callback is called if your AJAX query has failed
                alert("Errors!");
            }
        });
}

代码变量

<tr>
    <td class="col1"><label for="pat">Sucursal:</label></td>
    <td class="col2">
        <input type="text" name="suc" id="suc"  class="medium" readonly="true" style="width: 200px;"size="40" maxlength="200" onChange="javascript:this.value=this.value.toUpperCase();" />
        <input type="button" class="btn btn-success btn-sm" id="sbm" name="sbm" value="Buscar" onclick="llenaSucursales()" />
    </td>
</tr>

错误图片是：

这是一个问题吗？

我等待你的帮助，我开始阅读和搜索，但找不到错误

Answer 1

你应该看看jQuery documentation for $.ajax()，了解你可以用来对AJAX调用中的错误作出反应：

from __future__ import print_function

from inputs import get_key
from inputs import DeviceManager

def main():
    devices = DeviceManager()
    dictionaries = devices.codes
    qt = False
    while qt == False:
        events = get_key()
        for event in events:
            if (event.code in dictionaries["Key"].values() and event.code != "KEY_ESC" and event.state == 1):
                print(event.code, event.state)
            elif (event.code in dictionaries["Key"].values() and event.code == "KEY_ESC" and event.state == 1):
                qt = True
                break
    return

if __name__ == "__main__":
    main()

我还建议打开开发者工具（在大多数浏览器中使用F12）并检查＆＃34;网络选项卡＆＃34;查看AJAX调用的响应。

与您的问题无关：

将来请在撰写帖子时多加小心。删除不必要的空行，不要错误地发布代码（只关注你发布的重要部分） - 谢谢。

Answer 2

错误是我失踪了＆＃34; /＆＃34;文件的地址，谢谢，然后我留下代码

function empleados(){

 if($("#suc").val()=='')
    {
        alert('Elige una sucursal');
        return false;
    }
        $.ajax({
            url: '/emps.php',
            type: 'POST', // GET or POST
             data: {"suc":$("#suc").val()},
            success: function(data) { // data is the response from your php script
                // This function is called if your AJAX query was successful
              alert(data);
            },
            error: function() {  
                // This callback is called if your AJAX query has failed
                alert("Errors!");

            }
        });
}

POST变量错误

2 个答案: