Question

我想将日期时间值舍入到最近的整天。

UPDATE [DB].[dbo].[TABLE]
-- I'm unsure how to take the DepartureDate and round it up
SET DepartureDate = DepartureDate + ??
WHERE DATEPART(HOUR, DepartureDate) = 23

DepartureDate是datetime列。

因此2017-11-10 23:00:00.0000变为2017:11:11 00:00:00.0000

Answer 1

试试这个：

SELECT DepartureDate, 
       CASE WHEN DepartureDate = CONVERT(DATE, DepartureDate) 
            THEN DepartureDate 
            ELSE CONVERT(DATE,DepartureDate + 1)
       END RoundedDate
FROM YourTable;

这会将DepartureDate向下舍入到第二天，除非DepartureDate已经正好在午夜。它正在利用date类型的默认时间为午夜这一事实。

更新只会是：

UPDATE YourTable
SET DepartureDate = CASE WHEN DepartureDate = CONVERT(DATE, DepartureDate) 
                         THEN DepartureDate 
                         ELSE CONVERT(DATE,DepartureDate + 1)
                    END;

修改由于在评论中澄清了您只想在小时= 23时执行此操作，因此只需执行此操作：

UPDATE YourTable
SET DepartureDate = CONVERT(DATE,DepartureDate +1)
WHERE DATEPART(HOUR, DepartureDate) = 23

Answer 2

运行此选项，根据需要检查behviour轮次，然后应用于您的查询：

SELECT CAST(ROUND(CAST(getutcdate() as FLOAT),0) as datetime)

建议您使用旧日期和新日期选择您的数据，并首先进行眼球检查..更新前

Answer 3

如果您可以使用此脚本添加日期

，那么您在where子句中是正确的

select DATEADD(DD, 1,DepartureDate )

- 更新

UPDATE [DB].[dbo].[TABLE]
SET DepartureDate = DATEADD(DD, 1,DepartureDate )
WHERE DATEPART(HOUR, DepartureDate) = 23

SQL Server：Round Round Up

3 个答案: