Question

我正在使用jackson向我的控制器发送ajax json请求。这是我的实体：

@Entity
public class Template implements Serializable
{
    private String templateName;

    @ManyToMany(cascade = CascadeType.MERGE, fetch = FetchType.EAGER)
    private List<Action> actions;

    //getters setters
}

我的JSON看起来像：

"{"templateName":"aaa",
 "actions":["2", "3"]
}"

控制器：

 @RequestMapping(value = "/testCreate", consumes = MediaType.APPLICATION_JSON_VALUE)
    public @ResponseBody List<ObjectError> testCreate(@Valid @RequestBody final TemplateForm templateForm,
            final BindingResult bindingResult)
    {
        if (bindingResult.hasErrors())
        {
            return bindingResult.getAllErrors();
        }
        else
        {
            //some actions
            return EMPTY_LIST;
        }
    }

如何在Action对象列表中映射JSON中的动作ID？谢谢。

Answer 1

如果您使用的是Spring，可以使用 @InitBinder 。像这样：

@InitBinder
protected void initBinder(WebDataBinder binder) {
    binder.registerCustomEditor(ArrayList.class, "actions",
            new ActionEditor(actionService));
}

和ActionEditor将如下所示：

public class ActionEditor extends PropertyEditorSupport {

private final ActionService actionService;

public ActionEditor(ActionService actionService)    {
    this.ActionService = actionService;
}

@Override
public void setAsText(String text) throws IllegalArgumentException  {
    List<Action> facilities = new ArrayList<Action>();

    String[] ids = text.split(",");
    Set<Long> actionIds = new HashSet<Long>();
    for (String id : ids) {
        actionIds.add(Long.parseLong(id));
    }
    facilities.addAll(actionService.list(actionIds));
    setValue(facilities);
}}

将json id反序列化为对象列表

1 个答案: