Question

我有一个数组 - 像这样：

Array ( [0] => abc [1] => def [2] => ghi )

我有一个XML文件 - 就像这样：

<?xml version="1.0" encoding="utf-8" ?>
<ROOT>
  <SECTION>
    <PART1>abc</PART1>
    <PART2>111</PART2>
    <PART3>222</PART3>
  </SECTION>
  <SECTION>
    <PART1>def</PART1>
    <PART2>333</PART2>
    <PART3>444</PART3>
  </SECTION>
  <SECTION>
    <PART1>ghi</PART1>
    <PART2>555</PART2>
    <PART3>666</PART3>
  </SECTION>
</ROOT>

我需要的是在XML文件PART1中查找数组的所有值，并在新数组中输出PART2，然后看起来像这样：

Array ( [0] => 111 [1] => 333 [2] => 555 )

Answer 1

使用SimpleXMLElement类：

$arr = ['abc', 'def', 'ghi'];
$sxe = simplexml_load_file($your_xmlfile);
$part2 = [];

foreach ($sxe->SECTION as $s) {
    if (in_array($s->PART1, $arr)) $part2[] = (string) $s->PART2;
}
print_r($part2);

输出：

Array ( [0] => 111 [1] => 333 [2] => 555 )

Answer 2

您可以使用数组中的值来创建Xpath表达式，以获取所需的值：

import os
import csv
from collections import Counter, OrderedDict

def count_attributes(file_name):
    with open(file_name, encoding='utf-8', newline='') as csv_file:
        reader = csv.DictReader(csv_file)
        counters = OrderedDict((attr, Counter()) for attr in reader.fieldnames)
        for row in reader:
            for attr, value in row.items():
                counters[attr][value] += 1

    return counters

if __name__ == '__main__':
#    data_file = os.path.join("..", "data", "thecsvfile.csv")
    data_file = "thecsvfile.csv"  # Slight simplification for testing.
    for attr, counts in count_attributes(data_file).items():
        print('{}: {}'.format(attr.replace('_', ' '), dict(counts)))

使用数组在XML文件中查找并创建新数组

2 个答案: