有一个简单的(Angular 4)路由保护,它等待从后端加载一些数据:
@Injectable()
export class ContractsLoadedGuard implements CanActivate {
constructor(private store: Store<State>) { }
waitForData(): Observable<boolean> {
return this.store.select(state => state.contracts)
.map(contractList => !!contractList)
.filter(loaded => loaded)
.take(1);
}
canActivate(): Observable<boolean> { return this.waitForData(); }
}
路由:
const routes: Routes = [
{ path: 'app-list', canActivate: [ContractsLoadedGuard], component: AppListComponent },
];
最后@ ngrx / router-store v4 ROUTER_NAVIGATION
动作触发@ ngrx /效果:
@Effect() routeChange$ = this.actions$
.ofType(ROUTER_NAVIGATION)
.filter((action: RouterNavigationAction) => action.payload.routerState.url.indexOf('/app-list') > -1)
.withLatestFrom(this.store.select(state => state.contracts))
.switchMap(([action, contracts]: ([RouterNavigationAction, ContractList])) =>
this.restClient.load(action.payload.routerState.queryParams, contract));
不幸的是,当导航更改为/app-list
时,首先执行ngrx效果(保护之前),因此数据state.contracts
尚未可用。 守卫尚未执行。
我必须添加.combineLatest()
Rx运算符来等待有效的contracts
数据(这是后卫的工作):
@Effect() routeChange$ = this.actions$
.ofType(ROUTER_NAVIGATION)
.filter((action: RouterNavigationAction) => action.payload.routerState.url.indexOf('/app-list') > -1)
.combineLatest(this.contractListGuard.waitForContractsToLoad(), a => a) <- HERE
.withLatestFrom(this.store.select(state => state.contracts))
.switchMap(/* same here */)
我不确定这是否足够好。必须有一个更好的方法 - 不要重复有效的保护功能。
总结一下:在应用程序boostrap上,我需要从后端获取一些数据 - contracts
。如果用户导航到/app-list
(立即重定向),则会从服务器获取其他数据 - 基于某些查询参数和contracts
- ngrx路由器ROUTER_NAVIGATION
effect
执行顺序为在守卫执行命令之前。如何妥善处理?
答案 0 :(得分:1)
有一种方法可以实现它。您可以在效果中订阅Angular Router的ResolveEnd事件https://angular.io/api/router/ResolveEnd,然后为RESOLVE_END发送您自己的操作,您可以在其中处理您的解析器/警卫数据。
实际上我在ngrx / platform中创建了一个PR,其中ngrx / router将开箱即发送NAVIGATE_RESOLVE_END动作。我在等ngrx团队接受我的PR。 https://github.com/ngrx/platform/pull/524/
您可以订阅路由器事件并为Resolve End过滤它,并将您自己的操作调用称为Router_Resove_End action等。
this.router.events.filter(e => e instanceof ResolveEnd).subscribe(s => {
// dispatch your own action here.
});
答案 1 :(得分:0)
Medium上有很好的总结:
@Injectable()
export class RouterEffects {
constructor(
private actions$: Actions,private router: Router,private location: Location,private store: Store<any>
) {this.listenToRouter();}
@Effect({ dispatch: false })
navigate$ = this.actions$.pipe(ofType('[Router] Go')...);
@Effect({ dispatch: false })
navigateBack$ = this.actions$.pipe(ofType('[Router] Back'), tap(() => this.location.back()));
@Effect({ dispatch: false })
navigateForward$ = this.actions$.pipe(ofType('[Router] Forward'),...);
private listenToRouter() {
this.router.events.pipe(
filter(event => event instanceof ActivationEnd)
).subscribe((event: ActivationEnd) =>
this.store.dispatch(new RouteChange({
params: { ...event.snapshot.params },
path: event.snapshot.routeConfig.path
}))
);
}
}
然后代替:
@Effect() routeChange$ = this.actions$.ofType(ROUTER_NAVIGATION)
使用:
@Effect() routeChange$ = this.actions$.ofType(ofType('[Router] Route Change'))