Question

我正在创建一个csv文件并将其上传到ftp服务器。因此，上传包括该ftp服务器上多家公司的路径。

喜欢：

COMANY1 / FOO / BAR

但对于最后的一些公司，我得到了这个追溯：

Traceback (most recent call last):
  File "exporter.py", line 117, in <module>
    Exporter().run()
  File "exporter.py", line 115, in run
    self.upload(file, vendor['ftp_path'], filename)
  File "exporter.py", line 78, in upload
    sftp.chdir(dir)
  File "/home/johndoe/exports/daily/venv/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 580, in chdir
    if not stat.S_ISDIR(self.stat(path).st_mode):
  File "/home/johndoe/exports/daily/venv/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 413, in stat
    t, msg = self._request(CMD_STAT, path)
  File "/home/johndoe/exports/daily/venv/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 730, in _request
    return self._read_response(num)
  File "/home/johndoe/exports/daily/venv/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 781, in _read_response
    self._convert_status(msg)
  File "/home/johndoe/exports/daily/venv/local/lib/python2.7/site-packages/paramiko/sftp_client.py", line 807, in _convert_status
    raise IOError(errno.ENOENT, text)
IOError: [Errno 2] The requested file does not exist

我认为堆栈跟踪是指ftp路径，它不存在（但确实存在）。

但是当我尝试在那些完全相同的路径上运行该脚本（导致问题）时，它会通过吗？

所以，它不是一个逻辑错误，并且那些ftp路径确实存在 - 但它可能是由于某些超时发生了吗？

谢谢，汤姆

更新

我这样称呼方法：

self.upload(file, vendor['ftp_path'], filename)

进行上传的实际方法：

def upload(self, buffer, ftp_dir, filename):

    for dir in ftp_dir.split('/'):
        if dir == '':
            continue
        sftp.chdir(dir)

    with sftp.open(filename, 'w') as f:
        f.write(buffer)
    f.close()

    sftp.close()

上传到ftp服务器时Python脚本超时

0 个答案: