Question

我正在关注这个库以获取日期时间选择器https://github.com/florent37/SingleDateAndTimePicker它的工作正常但是如果我打开SingleDateAndTimePicker对话框并触发onBack按下方法然后对话框关闭但是我无法返回私有的活动，如果对话框是没有打开然后onBack新闻代码是火上任何解决方案，将不胜感激。我的代码：

 @Override
public void onBackPressed() {
    long currentTime = System.currentTimeMillis();
    if (singleDateAndTimePickerDialog!=null) {
        singleDateAndTimePickerDialog.dismiss();

    } else if (currentTime - lastPress > 5000) {
        Toast.makeText(getBaseContext(), "Press back again", Toast.LENGTH_LONG).show();
        lastPress = currentTime;
    } else {
        super.onBackPressed();
    }
}

Answer 1

你可以试试这个：

//一个全局变量 private SingleDateAndTimePickerDialog singleDateAndTimePickerDialog = null;

        onCreate(){ 
        singleDateAndTimePickerDialog = new SingleDateAndTimePickerDialog(this);
                   }

                   @Override
                   public void onBackPressed() {

        if(singleDateAndTimePickerDialog != null 
        && singleDateAndTimePickerDialog.isDisplaying()){

                     singleDateAndTimePickerDialog.dismiss();
                     return;
                    }//if

                      super.onBackPressed();
                      finish();

                    }

================================== EDIT ============ =========================

您可以使用Android DatePicker和TimePicker。

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout 
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:orientation="vertical"
    android:layout_width="match_parent"
    android:padding="8dp"
    android:layout_height="match_parent">

    <DatePicker
        android:id="@+id/date_picker"
        android:layout_width="match_parent"
        android:calendarViewShown="true"
        android:spinnersShown="false"
        android:layout_weight="4"
        android:layout_height="0dp" />

    <TimePicker
        android:id="@+id/time_picker"
        android:layout_weight="4"
        android:layout_width="match_parent"
        android:layout_height="0dp" />

    <Button
        android:id="@+id/date_time_set"
        android:layout_weight="1"
        android:layout_width="match_parent"
        android:text="Set"
        android:layout_height="0dp" />

</LinearLayout>

..和android对话框。

final View dialogView = View.inflate(activity, R.layout.date_time_picker, null);
final AlertDialog alertDialog = new AlertDialog.Builder(activity).create();

dialogView.findViewById(R.id.date_time_set).setOnClickListener(new View.OnClickListener() {
    @Override
    public void onClick(View view) {

         DatePicker datePicker = (DatePicker) dialogView.findViewById(R.id.date_picker);
         TimePicker timePicker = (TimePicker) dialogView.findViewById(R.id.time_picker);

         Calendar calendar = new GregorianCalendar(datePicker.getYear(),
                            datePicker.getMonth(),
                            datePicker.getDayOfMonth(),
                            timePicker.getCurrentHour(),
                            timePicker.getCurrentMinute());

         time = calendar.getTimeInMillis();
         alertDialog.dismiss();
    }});
alertDialog.setView(dialogView);
alertDialog.show();

所以你可以这样做：

   @Override
   public void onBackPressed() {

   if(alertDialog != null  && alertDialog.isShowing()){

   alertDialog.dismiss();
   return;
   }//if

   super.onBackPressed();
   finish();

   }

Answer 2

一旦对话被解雇，您可以尝试完成活动。

@RunWith(Parameterized.class)
public class SomeTest {

private final String PARAM_NAME = "param-1";

public SomeTest(String someParam){
    org.springframework.test.util.ReflectionTestUtils.setField(this, "PARAM_NAME", someParam);
}

@Parameterized.Parameters
public static Collection parameters() {
    return Arrays.asList(new Object[][] {
            { "param-1" },
            { "param-2" },
            { "param-3" }
    });
}

@Test
@ExternalAnnotation(PARAM_NAME) //needs constant in annotation
public void testSomething() throws Exception {
    System.out.println("Testing with: "+PARAM_NAME); //always prints param-1
    //some tests
    }
}

Answer 3

试试这个

@Override
public boolean onKeyDown(int keyCode, KeyEvent event) {
    if (keyCode == KeyEvent.KEYCODE_BACK) {
        onBackPressed();
    }
        return super.onKeyDown(keyCode, event);
    }
}

Answer 4

super.onBackPressed（）;

在其他条件下它对你的状况没问题，因为在这种情况下onback不会因为super.onback处于不正常状态而开火。

打开对话框时，onBackPress方法不会触发

4 个答案: