Question

我正在尝试将1到99之间的数字转换为单词形式，大于20的数字打印为“二十一”，“二十二”等等。不知道我的代码中缺少什么。

zero2nineteen = ['zero', 'one', 'two', 'three', 'four', 'five',
                 'six', 'seven', 'eight', 'nine', 'ten',
                 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 
                 'sixteen', 'seventeen', 'eighteen', 'nineteen']
zero2ninety = ['zero', 'ten', 'twenty', 'thirty', 'fourty',
               'fifty', 'sixty', 'seventy', 'eighty', 'ninety']

def number(Number):
    if (Number >= 1) or (Number <= 19):
        return (zero2nineteen[Number])
    elif (Number >= 20) or (Number <= 99):
        return (zero2ninety[Number])
    else:
        print("Done")

def main():
    Number = int(input("Please enter a number between 0 and 99: "))
    number(Number)

main()

Answer 1

首先，尽量避免对变量名使用大写单词 - 它们主要用于class定义。除此之外，您的转换逻辑不正确。您的number()方法会被修改，以便产生正确的结果：

def number(n):
    # 1. Rename variable
    # 2. Change "or" to "and"

    # If the number is between 0 and 19 (inclusive), refer directly to zero2nineteen list
    if (n >= 0) and (n <= 19):
        return (zero2nineteen[n])

    # If the number is between 20 and 99 (inclusive):
    elif (n >= 20) and (n <= 99):

        # First check if the number is a multiple of ten
        if not n % 10:

            # If it is, refer directly to the zero2ninety list
            return (zero2ninety[n // 10])

        # Else, use the zero2ninety list in conjunction with zero2nineteen
        return (zero2ninety[n // 10] + "-" + zero2nineteen[n % 10])

    # If the number is not between 0 and 99 inclusive, exit
    else:
        print("Done")

希望这有帮助！

Answer 2

导入变形 p = inflect.engine（） p.number_to_words（99） 99

在python中将数字转换为word形式时遇到问题

2 个答案: