Question

If I have an array of arrays and want to display them in a table, is there an efficient way to display them?

e.g.

Array
  (
  [0] => Array
    (
        [sku] => 1234
        [upc] => 6-00000-01234-5
        [measure_amount] => 30 
        [strength] => 100 mg
    )
  [1] => Array
    (
        [sku] => 5432
        [upc] => 6-00000-05432-1
    )
)

I'd like to output a table of all products but if the key doesn't exist just display a blank item. Right now, the only way I can think of doing this is iterate through every item, get the array_keys, combine them into a master key list and then use the key list to generate a table, but I think it would make more sense to do this:

Convert the above to:

Array
  (
  [0] => Array
    (
        [sku] => 1234
        [upc] => 6-00000-01234-5
        [measure_amount] => 30 
        [strength] => 100 mg
    )
  [1] => Array
    (
        [sku] => 5432
        [upc] => 6-00000-05432-1
        [measure_amount] =>
        [strength] =>
    )
)

I'm sure there's a better approach to this, like as I iterate through the list of items, merge the array with a model associative array... but I can't seem to get it to work.

Answer 1

您可以将array_map与array_merge结合使用：

$data = [
  ['sku' => 1, 'upc' => 'foo', 'measure_amount' => 30, 'strength' => '100mg'],
  ['sku' => 2, 'upc' => 'bar'],
];

$clean = array_map(function ($entry) use ($complete_item) {
     $all_keys = array_keys($complete_item);
     $empty = array_combine($all_keys, array_fill(0, count($all_keys), ''));
     return array_merge($empty, $entry);
   },
   $data
);

这将输出：

array(2) {
  [0]=>
  array(4) {
    ["sku"]=>
    int(1)
    ["upc"]=>
    string(3) "foo"
    ["measure_amount"]=>
    int(30)
    ["strength"]=>
    string(5) "100mg"
  }
  [1]=>
  array(4) {
    ["sku"]=>
    int(2)
    ["upc"]=>
    string(3) "bar"
    ["measure_amount"]=>
    string(0) ""
    ["strength"]=>
    string(0) ""
  }
}

Answer 2

嗯...现在你的帖子很有意义，你有条目有随机字段，但你希望返回一个数组，每个元素都有相同的字段。这是蛮力的方式......我确信有一个功能，但我不确定..

$merge = array();
// Run the array for all the fields and put them in merge.
foreach($array1 as $val)
{
    $merge = array_merge($merge,$val);
}
// Now run merge to set to a default...This probably has a function I don't use
foreach($merge as $key=>$val)
{
    $merge[$key] = '';
}
// Now Use Merge to put it all back
foreach($array1 as $key=>$val)
{
      $array1[$key] = array_merge($merge,$val);
}
// Your array1 now contains rows with all the same elements and in the same order.

Answer 3

此解决方案适用于子阵列中的大量子阵列和/或大量元素，因为它不需要额外的内存来存储其他空元素：

现在，我能想到的唯一方法是迭代每个项目，获取array_keys，将它们组合成一个主密钥列表然后使用密钥列表生成一个表。

如果您事先不知道子阵列中的具体密钥，请使用此密钥收集所有可能的密钥：

foreach ($mainArray as $subArray) {
   foreach ($subArray as $key=>$val) {
      if (!isset($allKeys[$key])) {
         $allKeys[$key] = '';
      }
   }
}

然后使用内部循环if (!isset($allKeys[$currentSubarrayKey]))检查打印空表格单元格，因为isset的工作速度比in_array快得多。

Answer 4

我建议使用您要创建的表的列创建第二个数组，而不是依赖于原始数组中的键。然后你可以这样循环：

$columns = array("sku","upc","measure_amount","strength");
foreach($mainArray as $a)
{
   foreach($columns as $col)
   {
      //Access the array element like this: $a[$col]
   }
}

注意：这只有在您事先知道密钥的情况下才有效。

Is there a Concise way to deal with PHP jagged associate arrays

4 个答案: