我试图找出Windows 10虚拟触摸键盘是否可见,以确定是否从我的应用程序中打开它。以下代码已经工作正常,直到最新的Windows 10更新15063或可能在它之前。似乎微软可能会改变窗口样式,但我无法弄明白。
public static bool IsKeyboardVisible()
{
IntPtr keyboardHandle = GetKeyboardWindowHandle();
// Specifies we wish to retrieve window styles.
int GWL_STYLE = -16;
//The window is disabled. See http://msdn.microsoft.com/en-gb/library/windows/desktop/ms632600(v=vs.85).aspx.
UInt32 WS_VISIBLE = 0x10000000;
UInt32 WS_DISABLED = 0x08000000;
UInt32 WS_POPUP = 0x80000000;
bool visible = false;
bool disabled = false;
if (keyboardHandle != IntPtr.Zero)
{
UInt32 style = GetWindowLong(keyboardHandle, GWL_STYLE);
visible = ((style & WS_VISIBLE) == WS_VISIBLE);
disabled = ((style & WS_DISABLED) == WS_DISABLED); // ref https://stackoverflow.com/questions/11065026/get-window-state-of-another-process
log.InfoFormat("style:{0:X4} visible:{1} disabled:{2}", style, visible, disabled);
}
return visible && !disabled ;
}
这与:Show touch keyboard (TabTip.exe) in Windows 10 Anniversary edition
有关答案 0 :(得分:5)
我用Spy++ 做了一些研究。看起来Fall Creators Update(版本1709)中的新键盘由另一个窗口托管。此窗口的标题为Windows.UI.Core.CoreWindow
,Microsoft Text Input Application
为其标题。
以下代码适用于所有Windows 10版本,包括新的1803及更早版本的Windows版本(我相信从Windows 8开始)。
static class TouchKeyboard
{
public static bool GetIsOpen()
{
return GetIsOpen1709() ?? GetIsOpenLegacy();
}
private static bool? GetIsOpen1709()
{
var parent = IntPtr.Zero;
for (;;)
{
parent = FindWindowEx(IntPtr.Zero, parent, WindowParentClass1709);
if (parent == IntPtr.Zero)
return null; // no more windows, keyboard state is unknown
// if it's a child of a WindowParentClass1709 window - the keyboard is open
var wnd = FindWindowEx(parent, IntPtr.Zero, WindowClass1709, WindowCaption1709);
if (wnd != IntPtr.Zero)
return true;
}
}
private static bool GetIsOpenLegacy()
{
var wnd = FindWindowEx(IntPtr.Zero, IntPtr.Zero, WindowClass);
if (wnd == IntPtr.Zero)
return false;
var style = GetWindowStyle(wnd);
return style.HasFlag(WindowStyle.Visible)
&& !style.HasFlag(WindowStyle.Disabled);
}
private const string WindowClass = "IPTip_Main_Window";
private const string WindowParentClass1709 = "ApplicationFrameWindow";
private const string WindowClass1709 = "Windows.UI.Core.CoreWindow";
private const string WindowCaption1709 = "Microsoft Text Input Application";
private enum WindowStyle : uint
{
Disabled = 0x08000000,
Visible = 0x10000000,
}
private static WindowStyle GetWindowStyle(IntPtr wnd)
{
return (WindowStyle)GetWindowLong(wnd, -16);
}
[DllImport("user32.dll", SetLastError = false)]
private static extern IntPtr FindWindowEx(IntPtr parent, IntPtr after, string className, string title = null);
[DllImport("user32.dll", SetLastError = false)]
private static extern uint GetWindowLong(IntPtr wnd, int index);
}
更新:我更新了答案以及与Redstone 4(v1803)兼容的代码。
答案 1 :(得分:0)
我正在使用此解决方案,并且它可以在Windows 1607、1709和1803上运行(请在代码中检查下面的Main方法):
using System;
using System.Drawing;
using System.Runtime.InteropServices;
namespace ConsoleApp1
{
class Program
{
[ComImport, Guid("D5120AA3-46BA-44C5-822D-CA8092C1FC72")]
public class FrameworkInputPane
{
}
[ComImport, System.Security.SuppressUnmanagedCodeSecurity,
InterfaceType(ComInterfaceType.InterfaceIsIUnknown),
Guid("5752238B-24F0-495A-82F1-2FD593056796")]
public interface IFrameworkInputPane
{
[PreserveSig]
int Advise(
[MarshalAs(UnmanagedType.IUnknown)] object pWindow,
[MarshalAs(UnmanagedType.IUnknown)] object pHandler,
out int pdwCookie
);
[PreserveSig]
int AdviseWithHWND(
IntPtr hwnd,
[MarshalAs(UnmanagedType.IUnknown)] object pHandler,
out int pdwCookie
);
[PreserveSig]
int Unadvise(
int pdwCookie
);
[PreserveSig]
int Location(
out Rectangle prcInputPaneScreenLocation
);
}
static void Main(string[] args)
{
var inputPane = (IFrameworkInputPane)new FrameworkInputPane();
inputPane.Location(out var rect);
Console.WriteLine((rect.Width == 0 && rect.Height == 0) ? "Keyboard not visible" : "Keyboard visible");
}
}
}
它使用 IFrameworkInputPane 接口(https://docs.microsoft.com/en-us/windows/desktop/api/shobjidl_core/nn-shobjidl_core-iframeworkinputpane)