Question

标题听起来可能比它复杂。

我有两个阵列，由两个不同的地图创建。然后我继续循环遍历每个数组：

let temp = [];
    let temp2 = [];

    nameArray.forEach(function(x){
        temp.push({question: x[0]})
    })
    bodyArray.forEach(function(x){
        temp2.push({answer: x[0]})
    })

给我结果：

[0:{question: "generic question"}
 1:{question:...}
 2:{...}]

和

[0:{answer: "generic answer"}
 1:{answer:...}
 2:{...}]

我最终得到的是一个对象列表，并且对象是两个数组中的对象，但是合并如下：

[0:{question: "generic question", answer: "generic answer"}]

Answer 1

您可以使用array#map并遍历您的问题数组，并使用question数组的索引，您可以添加answer数组中的元素，并生成带有这两个问题的对象数组并回答。

＆＃13;

const questions = ["generic question", "generic question 12", "generic question 34"],
      answers = ["generic answer", "generic answer 12", "generic answer 34"];

const merged = questions.map((question, i) => ({question, 'answer' : answers[i]}));
console.log(merged);

＆＃13;

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＆＃13;

Answer 2

您可以对每个questions进行迭代，然后使用.forEach()合并它们：

let questions = [
{question: "Question?"},
{question: "Question 2"},
];

let answers = [
{answer: "Yes"},
{answer: "no"}
];

questions.forEach((question, i) => question["answer"] = Object.values(answers[i])[0]);

哪个输出：

 [ 0: {question: "Question?", answer: "Yes"},
1: {question: "Question 2", answer: "no"} ]

Answer 3

您可以为其获取任意数量的属性和所需数组，并构建新对象。

var questions = ['question1', 'question2', 'question3'],
    answers = ['answer1', 'answer2', 'answer3'],
    keys = ['question', 'answer'],
    result = [questions, answers].reduce(function (r, a, i) {
        a.forEach(function (v, j) {
            r[j] = r[j] || {};
            r[j][keys[i]] = v;
        });
        return r;
    }, []);

console.log(result);

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如何将两个对象列表合并为一个对象列表，同时合并对象

3 个答案: