mySQL pivot动态日期表

Question

我正在运行我的查询

SELECT
DATE_FORMAT(FROM_DAYS(TO_DAYS(st_day_request) -MOD(TO_DAYS(st_day_request) -2, 7)), '%d-%m-%Y') as DATE,
tx_report_id AS 'BUSINESS',
CONCAT(ROUND(AVG(DATEDIFF(dt_dossier_sent,st_day_request) > -5 AND (main.dt_dossier_sent IS NOT NULL AND main.dt_dossier_sent <> '0000-00-00')) * 100),'%') as DISPATCHED_5_AND_MORE,
CONCAT(ROUND(AVG(DATEDIFF(dt_dossier_sent,st_day_request) < -5 AND DATEDIFF(dt_dossier_sent,st_day_request) <= 1 AND (main.dt_dossier_sent IS NOT NULL AND main.dt_dossier_sent <> '0000-00-00')) * 100),'%') as DISPATCHED_4_TO_1,
CONCAT(ROUND(AVG(DATEDIFF(dt_dossier_sent,st_day_request) > 1 AND DATEDIFF(dt_dossier_sent,st_day_request) <= 10 AND (main.dt_dossier_sent IS NOT NULL AND main.dt_dossier_sent <> '0000-00-00')) * 100),'%') as DISPATCHED_2_TO_10,
CONCAT(ROUND(AVG(DATEDIFF(dt_dossier_sent,st_day_request) > 10 AND (main.dt_dossier_sent IS NOT NULL AND main.dt_dossier_sent <> '0000-00-00')) * 100),'%') as DISPATCHED_10_AND_MORE,
CONCAT(ROUND(AVG(main.dt_dossier_sent IS NULL OR main.dt_dossier_sent = '0000-00-00') * 100),'%') as OUTSTANDING FROM
(
SELECT 
    app_contract.id_app,
    app_contract.dt_dossier_sent,
    contract.tx_report_id,
    contract.st_day_request
FROM
    contract
INNER JOIN app_contract ON  app_contract.id_contract = contract.id_contract  AND contract.st_day_request > '2017-09-01' AND contract.id_client = 657
INNER JOIN app_hist ON app_hist.id_app=app_contract.id_app
GROUP BY app_contract.id_app
) as main GROUP BY DATE ORDER BY DATE_FORMAT(st_day_request, '%y') ASC, DATE_FORMAT(st_day_request, '%m') ASC

并在下面的图片中获得结果：

到此为止，一切都是正确的。我遇到的问题是我想要更改（pivot / crosstab）我的结果并将我得到的日期作为列，如下图所示：

我正在尝试几天，但遗憾的是没有结果。有任何想法吗？

PS。如果您无法正确查看图像，请右键单击并在新选项卡中打开。然后你可以放大它们。对不起图片，我会在下一篇文章中复制并粘贴结果。

Answer 1

关注标签 - 有很多关于如何在MySQL中执行此操作的示例。此外，这是一种从MySQL存储过程生成SQL的自动方法：http://mysql.rjweb.org/doc.php/pivot

（就个人而言，我使用通用的PHP代码将3列表转换为矩阵。）