Groovy替代Java8的.map（）流操作

Question

什么是Groovy替代Java 8的.map()？

示例：

List<String> codes = events
    .stream()
    .map(event -> event.getCode())
    .collect(Collectors.toList());

我正在尝试

events.each { it; return it.getCode() }.collect() as String[]

但我得到List String个toString()代表而不是代码

Answer 1

考虑collect方法，如下所示：

class Event {
    def code
    def name
}

def events = []
events << new Event(code: '001', name: 'a')
events << new Event(code: '002', name: 'b')

def codes = events.collect { it.code }

assert ['001','002'] == codes