Question

这是我的代码 -

$sql="SELECT * FROM payment WHERE customerid='$id'";
if ($result=mysqli_query($con,$sql))
  {
  while ($row=mysqli_fetch_assoc($result);
    {
    echo $row['fraction_payment'];
    }    
}

我想尝试做什么：不断添加$row['fraction_payment']与之前的值。

如果数据库值为

fraction_payment 1 = 100 
fraction_payment 2 = 200 
fraction_payment 3 = 300

预期结果将是：

$row['fraction_payment'][1] = 100
$row['fraction_payment'][2] = 300
$row['fraction_payment'][3] = 600

我应该如何在PHP中继续这样做？

Answer 1

这应该是诀窍，非常自我解释：

$total = 0;
$sql="SELECT * FROM payment WHERE customerid='$id'";
if ($result=mysqli_query($con,$sql))
{
  while ($row=mysqli_fetch_assoc($result);
  {
    $total += $row['fraction_payment'];
    echo $total;
  }    
}

Answer 2

$sql="SELECT * FROM payment WHERE customerid='$id'";
if ($result = mysqli_query($con,$sql))
{
  $sum = 0;
  $result = [];
  while ($row = mysqli_fetch_assoc($result);
  {
    $sum += $row['fraction_payment'];
    $result[] = $sum;
  }
  var_dump($result);
}

并且不要忘记SQL注入：How can I prevent SQL injection in PHP?

PHP SQL继续使用之前的内部循环添加row ['value']

2 个答案: