Question

我需要你的帮助。你能帮我写一个输出平均值的查询吗？我有3个项目 - GAO，GAD和GAM以及每个项目我需要计算表格底部的平均值，在“ALL”下面。查询：

SELECT NVL(vrz.DATA, 'ALL') AS DAY,
SUM(vrz.SOV_GAO_1_ILE) AS GAO,
SUM(vrz.SOV_GAD_2_ILE) AS GAD,
SUM(vrz.SOV_GAM_3_ILE) AS GAM,
SUM(vrz.SOV_GAO_1_ILE) + SUM(vrz.SOV_GAD_2_ILE) + SUM(vrz.SOV_GAM_3_ILE) AS SUMMARY,
FLOOR((SUM(vrz.SOV_GAO_1_ILE) + SUM(vrz.SOV_GAD_2_ILE) + 
SUM(vrz.SOV_GAM_3_ILE))/3) AS AVERAGE
FROM PLC.V_RAPORT_ZDARZEN vrz
GROUP BY ROLLUP (vrz.DATA)

部分数据：

DAY         GAO     GAD     GAM   SUMMARY   AVERAGE
2017-05-25  1035,0  725,0   0,0   1760,0    586,0
2017-05-26  253,0   785,0   0,0 1038,0  346,0
2017-05-29  1060,0  467,0   0,0 1527,0  509,0
2017-05-30  922,0   905,0   0,0 1827,0  609,0
2017-05-31  1113,0  1343,0  0,0 2456,0  818,0
2017-06-01  1236,0  1057,0  0,0 2293,0  764,0
2017-06-02  1740,0  1182,0  0,0 2922,0  974,0
2017-06-04  22,0    1,0 0,0 23,0    7,0
2017-06-05  1702,0  1534,0  0,0 3236,0  1078,0
2017-06-06  1754,0  1388,0  0,0 3142,0  1047,0
2017-06-07  865,0   1109,0  0,0 1974,0  658,0
2017-06-08  1248,0  1044,0  0,0 2292,0  764,0
2017-06-09  752,0   978,0   0,0 1730,0  576,0
2017-06-12  1403,0  534,0   0,0 1937,0  645,0
2017-06-13  2415,0  850,0   0,0 3265,0  1088,0
2017-06-14  1159,0  458,0   0,0 1617,0  539,0
2017-06-16  361,0   372,0   0,0 733,0   244,0
2017-06-19  1605,0  393,0   0,0 1998,0  666,0
2017-06-20  938,0   694,0   0,0 1632,0  544,0
2017-06-21  2212,0  952,0   0,0 3164,0  1054,0
2017-06-22  1912,0  922,0   0,0 2834,0  944,0
2017-06-23  1030,0  1003,0  0,0 2033,0  677,0
2017-06-26  528,0   111,0   0,0 639,0   213,0
2017-06-27  910,0   485,0   0,0 1395,0  465,0
2017-06-28  708,0   240,0   0,0 948,0   316,0
2017-06-29  1819,0  1122,0  0,0 2941,0  980,0
.......
2017-11-03  809,0   585,0   600,0   1994,0  664,0
2017-11-06  953,0   1474,0  595,0   3022,0  1007,0
2017-11-07  800,0   1250,0  991,0   3041,0  1013,0
2017-11-08  0,0     615,0   1014,0  1629,0  543,0
ALL         131029,0    124262,0    112195,0    367486,0    122495,0

平均值： GAO GAD GAM 1082,884298 1027,834711 927,231405

感谢您的帮助！

Picture that illustrates my data

Answer 1

Rollup没问题，但在这种情况下，我会使用CTE并使用union all添加两个摘要行。

with cte as (
    select data, count(1) cnt,
           sum(sov_gao_1_ile) gao, sum(sov_gad_2_ile) gad, sum(sov_gam_3_ile) gam,
           sum(sov_gao_1_ile + sov_gad_2_ile + sov_gam_3_ile) / 3 average
      from vrz
      group by data)
select to_char(data, 'yyyy-mm-dd') data, gao, gad, gam, gao+gad+gam summary, average 
  from cte
union all 
select 'ALL', sum(gao), sum(gad), sum(gam), sum(gao+gad+gam), sum(average)
  from cte
union all
select 'AVG', round(avg(gao)), round(avg(gad)), round(avg(gam)), null, null
  from cte
  order by 1

据我所知，您需要已经分组数据的平均值，这可能与整个数据的平均值不同。如果没有，那么@ Wernfried的解决方案应该对你有用。无论如何，您可以使用列cnt来按计数来划分总和。将来请提供完整的数据和匹配输出，这样我们就可以验证结果。

工会处理受到侵害的款项，因此不应影响业绩。简化的演示数据和输出：

with vrz(data, sov_gao_1_ile, sov_gad_2_ile, sov_gam_3_ile) as (
    select date '2000-01-21', 111, 112, 114 from dual union all
    select date '2000-01-21', 115, 116, 125 from dual union all
    select date '2000-01-22', 211, 212, 213 from dual union all
    select date '2000-01-22', 215, 216, 223 from dual union all
    select date '2000-01-23', 301, 302, 225 from dual),
cte as (
    select data, count(1) cnt,
           sum(sov_gao_1_ile) gao, sum(sov_gad_2_ile) gad, sum(sov_gam_3_ile) gam,
           sum(sov_gao_1_ile + sov_gad_2_ile + sov_gam_3_ile) / 3 average
      from vrz
      group by data)
select to_char(data, 'yyyy-mm-dd') data, gao, gad, gam, gao+gad+gam summary, average 
  from cte
union all 
select 'ALL', sum(gao), sum(gad), sum(gam), sum(gao+gad+gam), sum(average) 
  from cte
union all
select 'AVG', round(avg(gao)), round(avg(gad)), round(avg(gam)), null, null 
  from cte
  order by 1



DATA              GAO        GAD        GAM    SUMMARY    AVERAGE
---------- ---------- ---------- ---------- ---------- ----------
2000-01-21        226        228        239        693        231
2000-01-22        426        428        436       1290        430
2000-01-23        301        302        225        828        276
ALL               953        958        900       2811        937
AVG               318        319        300

Answer 2

一个简单的解决方案就是这个：

SELECT NVL(vrz.DATA, 'ALL') AS DAY,
   SUM(vrz.SOV_GAO_1_ILE) AS GAO,
   SUM(vrz.SOV_GAD_2_ILE) AS GAD,
   SUM(vrz.SOV_GAM_3_ILE) AS GAM,
   SUM(vrz.SOV_GAO_1_ILE) + SUM(vrz.SOV_GAD_2_ILE) + SUM(vrz.SOV_GAM_3_ILE) AS SUMMARY,
   FLOOR((SUM(vrz.SOV_GAO_1_ILE) + SUM(vrz.SOV_GAD_2_ILE) + SUM(vrz.SOV_GAM_3_ILE))/3) AS AVERAGE
FROM PLC.V_RAPORT_ZDARZEN vrz
GROUP BY ROLLUP (vrz.DATA)
UNION ALL
SELECT 'AVG', 
   AVG(vrz.SOV_GAO_1_ILE),
   AVG(vrz.SOV_GAD_2_ILE),
   AVG(vrz.SOV_GAM_3_ILE),
   NULL, NULL
FROM PLC.V_RAPORT_ZDARZEN vrz;

但是，就性能而言，它可能不是最佳解决方案。

显示查询底部每列的平均值

2 个答案: