所以我将这个矩形向右移动。如何在矩形到达边界时让矩形反转它。我试图让它来回走动。
<!DOCTYPE html>
<html>
<head>
<script type='text/javascript'>
window.onload=function(){
var canvas = document.getElementById('canvas');
var ctx = canvas.getContext('2d');
var x = 0;
var y = 50;
var width = 10;
var height = 10;
function animate() {
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.fillRect(x, y, width, height);
x++;
if(x <= 490) {
setTimeout(animate, 33);
}
}
animate();
}
</script>
</head>
<body>
<canvas id="canvas" width="500" height="400"
style="border: 1px solid #000000;"></canvas>
</body>
</html>
答案 0 :(得分:0)
https://codepen.io/forTheLoveOfCode/pen/wqdpeg
这就是你需要的吗? (链接到上面的codepen)。
var canvas = document.getElementById("canvas_id");
var context = canvas.getContext('2d');
var x=5;
var y=5;
var velocity = 10;
function move(){
canvas.width = window.innerWidth;
canvas.height = window.innerHeight;
x =x + velocity
if ((x+50)>canvas.width || x<0){
velocity *=-1;
}
draw()
}
function draw(){
context.fillStyle = "#E80C7A";
context.strokeStyle = "#000000";
context.lineWidth = '3';
context.fillRect(x, y, 50, 100);
context.strokeRect(x, y, 50, 100);
}
setInterval(move, 100);
<html>
<body>
<canvas id = "canvas_id">
</canvas>
</body>
</html>
答案 1 :(得分:0)
这是一个带边界检测的解决方案
window.onload=function(){
var canvas = document.getElementById('canvas');
var ctx = canvas.getContext('2d');
var x = 0;
var y = 50;
var width = 10;
var height = 10;
var speed = 10; // speed
function animate() {
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.fillRect(x, y, width, height);
if(
(x >= 500 - width && speed > 0) || // going to the right and bound reached
(x <= 0 && speed < 0) // going to the left and bound reached
) {
speed *= -1; // inverting the direction
}
x += speed;
setTimeout(animate, 33);
}
animate();
}
<canvas id="canvas" width="500" height="400"
style="border: 1px solid #000000;"></canvas>
考虑使用requestAnimationFrame代替setTimeout
来完成此类工作。